Document2 - Arkansas Tech University

2cosx— 1 = 0 cosx 3000 The solutions are 600 smx , 900, sm x x 3000 . 53. 2sinx — 3cosx = 1 2sinx — 3cosx+1 (2 sinx) (3 cosx + 1) 4sin x —9cos x +6cosx+1 4(1—cos x+6cosx+1 O = 13cos2 x +6cosx —3 62 — cosx 203) _6±v'î5î cosx 0.3022 ... tan 2x tan 2x where k is an Integer 2 65. 2 sin x cos x sm x(2 cos x 0 smx 0 2cosx —1 cosx ... ................
................