Curriculum Cluster 2
4y = 3x + 12. y = x + 3. The slope of this line is. The slope of a line perpendicular to it will be the opposite reciprocal of . The new slope to use will be . The equation of the line that goes through ( 1, -5 ) and has slope is . y – ( -5) = ( x – 1) y + 5 = + y = - This line is perpendicular to the line whose equation is – 3x + 4y = 12. ................
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