Inverse Manipulator Kinematics (1/3) - UCLA
Inverse Manipulator Kinematics (1/3)
Direct Versus Inverse Kinematics
Direct (Forward) Kinematics
Given: Joint angles and links geometry Compute: Position and orientation of the end
effector relative to the base frame
f ( )BTT N0T
Inverse Kinematics
Given: Position and orientation of the end effector relative to the base frame
Compute: All possible sets of joint angles and links geometry which could be used to attain the given position and orientation of the end effetor
f 1(BTT ) f 1(N0T )
Central Topic - Inverse Manipulator Kinematics Examples
? Geometric Solution - Concept Decompose spatial geometry into several plane geometry
Examples - Planar RRR (3R) manipulators Geometric Solution
? Algebraic Solution - Concept
r11 r12 r13 px
N0T 01TN N1T
r21 r31
r22 r32
r23 r33
p
y
pz
0
0
0
1
Direct Kinematics Goal (Numeric values)
Examples - PUMA 560 - Algebraic Solution
Solvability - PUMA 560
Given : PUMA 560 - 6 DOF, 06T
Solve: 16
r11 r12 r13 px
06T 01T 12T 23T 34T 45T 56T
r21 r31
r22 r32
r23 r33
p
y
pz
0
0
0
1
Total Number of Equations: 12
Independent Equations: 3 - Rotation Matrix 3 - Position Vector
Type of Equations: Non-linear
Solvability
? Existence of Solutions ? Multiple Solutions ? Method of solutions
? Close form solution ? Algebraic solution ? Geometric solution
? Numerical solutions
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