CambridgeInternationalExaminations ...
*9782733059*
PMT
Cambridge International Examinations Cambridge International Advanced Level
CANDIDATE NAME
CENTRE NUMBER
CANDIDATE NUMBER
MATHEMATICS Paper 3 Pure Mathematics 3 (P3)
Candidates answer on the Question Paper. Additional Materials: List of Formulae (MF9) READ THESE INSTRUCTIONS FIRST
9709/32 October/November 2018
1 hour 45 minutes
Write your Centre number, candidate number and name in the spaces at the top of this page. Write in dark blue or black pen. You may use an HB pencil for any diagrams or graphs. Do not use staples, paper clips, glue or correction fluid. DO NOT WRITE IN ANY BARCODES.
Answer all the questions in the space provided. If additional space is required, you should use the lined page at the end of this booklet. The question number(s) must be clearly shown. Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place in the case of angles in degrees, unless a different level of accuracy is specified in the question. The use of an electronic calculator is expected, where appropriate. You are reminded of the need for clear presentation in your answers.
At the end of the examination, fasten all your work securely together. The number of marks is given in brackets [ ] at the end of each question or part question. The total number of marks for this paper is 75.
JC18 11_9709_32/RP ? UCLES 2018
This document consists of 19 printed pages and 1 blank page.
[Turn over
PMT
2
1 Solve the inequality 3 2x - 1 > x + 4 .
[4]
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
? UCLES 2018
9709/32/O/N/18
PMT
3 2 Showing all necessary working, solve the equation sin - 30 + cos = 2 sin , for 0 < < 180 .
[4] ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................
? UCLES 2018
9709/32/O/N/18
[Turn over
PMT
4
ln x
3
(i) Find x3 dx.
[3]
........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................
2
(ii) Hence show that
ln x x3
dx
=
1 16
3 - ln 4
.
[2]
1
........................................................................................................................................................
........................................................................................................................................................
........................................................................................................................................................
........................................................................................................................................................
........................................................................................................................................................
........................................................................................................................................................
........................................................................................................................................................
? UCLES 2018
9709/32/O/N/18
PMT
5
4 Showing all necessary working, solve the equation
ex + e-x ex + 1
=
4,
giving your answer correct to 3 decimal places.
[5]
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
................................................................................................................................................................
? UCLES 2018
9709/32/O/N/18
[Turn over
................
................
In order to avoid copyright disputes, this page is only a partial summary.
To fulfill the demand for quickly locating and searching documents.
It is intelligent file search solution for home and business.
Related download
- cambridge assessment international education cambridge
- cambridge exam entry subject and option codes as
- research article design installation and
- bifurcations for a driven damped pendulum
- graad 12 national senior certificate grade 12
- cambridge international as a level physics 9702
- cambridge international examinations cambridge
- cambridgeinternationalexaminations
- cambridge exam entry subject and option codes as level
- english home language p3 memorandum