The S A T® - SAT Suite of Assessments
equals, negative x. squared, plus 5 x. Subtracting . c. from both sides of . c. equals, negative x. squared, plus 5 x. and then dividing both sides by negative 1 yields 0 equals, x squared, minus 5 x, plus . c. The solution to this quadratic equation would give the . x. coordinate(s) of the point(s) of intersection. ................
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