Algebra Chapter 3 Test - Kyrene School District



Algebra Chapter 3 Practice Test Name: _______________________________ Date: ___________________Directions: In problems 1 – 10, solve the equation. Show all work.1. 14j = 44 2. –y + 8 = -9 33. 6m - 11 = 214. 6y + 5 = 9y – 7 5. 2n – 6(2 + 3n) = 206. | -3 |b – 4(2 – 3b) = 197. xy + h = w Solve for y.8. ab – ce = dSolve for e. j9. a + e = dSolve for b.10. a + b = dSolve for b. c b c - e 11. The triangle has a perimeter of 41 centimeters. Solve for the missing sides.10160026035103x + 2x + 100103x + 2x + 13087370275590r00r12. The circle has a circumference of 18 in. Approximate the radius of the circle. Give your answers in terms of π.13. One video rental club charges $25 to become a member and $2.00 to rent each video. Another charges no membership fee, but charges $2.75 to rent each video. How many videos must you rent to make the first club more economical?______ 14. Solve -3x – 6 = 4x + 8a) -2 b) 2 c) -14 d) 14 e) -1_____ 15. Solve 5x – 12 = 3x + 6a) - 2? b) 2? c) ? d) –? e) 9_____ 16. Solve 23 (9x – 13) + 7 = 12 – 6x a) -4/3 b)11/8 c) 4/3 d)11/9 e) 18_____ 17. Solve 4x + 7 = 8x + 7a) 7/2 b) -7/2 c) -3 d) 3 e) 018. Your club decides to sell cookie dough to raise money. Every pound costs you $3.50 and there is a one time delivery fee of $45. You plan to sell the stationery for $7 per box. Which equation should you use to determine how many boxes you must sell to cover your costs?a) 3.50p – 45 = 7pb) 45 – 7p = 3.50pc) 3.50p + 45 = 7pd) 45 – 3.50p = 7pe) 7p + 45 = 3.50pDirections: In exercises 19 & 20, choose the statement below that is true about the given number.a) The solution in column A is greater.b) The solution in column B is greater.c) The two solutions are equal.d) The relationship cannot be determined from the given information.Column AColumn B19.x + 6 = |-4|y – 4 = -620.x + | -5 | = 63 = y + 719. _____20. _____Bonus: Solve for n. Show all steps! 5 + 2n = 12 7m - 1 ................
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