AP Biology 2021 Free-Response Questions - College Board

2021

AP? Biology

Free-Response Questions

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AP? BIOLOGY EQUATIONS AND FORMULAS

Statistical Analysis and Probability

Mean

Standard Deviation

n

? x

=

1 n

xi

i =1

s =

? (xi - x )2 n -1

Standard Error of the Mean

SEx =

s n

Chi-Square

2 o e2 e

Chi-Square Table

p

Degrees of Freedom

value 1

2

3

4

5

6

7

8

0.05 3.84 5.99 7.81 9.49 11.07 12.59 14.07 15.51

0.01 6.63 9.21 11.34 13.28 15.09 16.81 18.48 20.09

x = sample mean

n = sample size

s = sample standard deviation (i.e., the sample-based estimate of the standard deviation of the population)

o = observed results

e = expected results

= sum of all

Degrees of freedom are equal to the number of distinct possible outcomes minus one.

Laws of Probability If A and B are mutually exclusive, then:

P(A or B) = P(A) + P(B) If A and B are independent, then:

P(A and B) = P(A) P(B)

Hardy-Weinberg Equations

p2 + 2pq + q2 = 1 p + q = 1

p = frequency of allele 1 in a population

q = frequency of allele 2 in a population

Factor

10 9 10 6 10 3 10? 1 10? 2 10 ? 3 10 ? 6 10 ? 9 10 ? 12

Metric Prefixes

Prefix

giga mega kilo deci centi milli micro nano pico

Symbol

G M k d c m n p

Mode = value that occurs most frequently in a data set Median = middle value that separates the greater and lesser halves of a data set Mean = sum of all data points divided by number of data points Range = value obtained by subtracting the smallest observation (sample minimum) from the greatest (sample maximum)

Rate and Growth

Rate dY dt

Population Growth

dN dt

=

B-D

Exponential Growth

dN dt

= rmax N

dY = amount of change dt = change in time B = birth rate D = death rate N = population size K = carrying capacity rmax = maximum per capita

growth rate of population

Logistic Growth

( ) dN

dt

= rmax N

K -N K

Simpson's Diversity Index

( ) Diversity Index =

1- ?

n N

2

total number of organisms of a particular species

total number of organisms of all species

Water Potential ( Y )

Y = YP + YS

YP = pressure potential

YS = solute potential

The water potential will be equal to the solute potential of a solution in an open container because the pressure potential of the solution in an open container is zero.

The Solute Potential of a Solution

YS = -iCRT

i = ionization constant (1.0 for sucrose because sucrose does not ionize in water)

C = molar concentration

R = pressure constant ( R = 0.0831 liter bars/mole K)

T = temperature in Kelvin (?C + 273)

pH = ? log[H+] Surface Area and Volume

Surface Area of a Sphere SA 4 r 2

Surface Area of a Rectangular Solid SA 2lh 2lw 2wh

Surface Area of a Cylinder SA 2 rh 2 r 2

Surface Area of a Cube SA 6s2

Volume of a Sphere

V

4 3

r 3

Volume of a Rectangular Solid

V lwh

Volume of a Cylinder V r2h

Volume of a Cube V s3

r = radius l = length

h = height w = width s = length of one

side of a cube SA = surface area V = volume

AP? Biology 2021 Free-Response Questions

BIOLOGY SECTION II Time--1 hour and 30 minutes 6 Questions

Directions: Questions 1 and 2 are long free-response questions that require about 25 minutes each to answer. Questions 3 through 6 are short free-response questions that require about 10 minutes each to answer. Read each question carefully and completely. Answers must be written out in paragraph form. Outlines, bulleted lists, or diagrams alone are not acceptable. You may plan your answers in this orange booklet, but no credit will be given for anything written in this booklet. You will only earn credit for what you write in the separate Free Response booklet.

Question 1 is on the following page.

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AP? Biology 2021 Free-Response Questions

1. Polycystic kidney disease (PKD) is an inherited disease that causes water loss from the body and affects cell division in the kidneys. Because water movement across cell membranes is related to ion movement, scientists investigated the role of the Na+/K+ATPase (also known as the sodium/potassium pump) in this disease. Ouabain, a steroid hormone, binds to the Na+/K+ATPase in plasma membranes. Individuals with PKD have a genetic mutation that results in an increased binding of ouabain to the Na+/K+ATPase. The scientists treated normal human kidney (NHK) cells and PKD cells with increasing concentrations of ouabain and measured the number of cells (Figure 1) and the activity of the Na+ / K+ATPase (Figure 2) after a period of time. The scientists hypothesized that a signal transduction pathway that includes the protein kinases MEK and ERK (Figure 3) may play a role in PKD symptoms.

Figure 1. Cell number compared with the number of cells at 0 pM ouabain. Normal human kidney (NHK) Figure 2. Percent Na+/K+ATPase activity of NHK and cells and polycystic kidney disease (PKD) cells were PKD cells treated with increasing concentrations of treated with increasing concentrations of ouabain. Error ouabain. Error bars represent ?2SE x. bars represent ?2SE x.

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