Part III: Substituting numbers and solving expressions

 AP PHYSICS I SUMMER ASSIGNMENTDr. Prencipe Welcome to AP Physics I! Thank you for your interest in studying physics next year. The summer assignment consists of mathematical skills and tasks that must be completed before the commencement of the next school year. Please be advised: the written assignment is due on the first day of school! There will be an assessment on the first day of school. This is a college level course, so expect to be challenged. You need to become involved in your own education. You have to participate, practice, ask for help and always show all of your work. I am looking forward to a successful school year. Enjoy your summer! Name: Summer Assignment 2020 AP Physics IPart 1: Scientific Notation: Part II- Solving for the unknown variableMake sure to show ALL YOUR WORK and ALL STEPS. Writing down the answer only will not get you full credit. CIRCLE all your answers!!! Solve the following equations for the quantity indicated. Often problems on the AP Exam are solved with variables only. Below are some physics formulas that may or may not be familiar to you. Don’t worry about what the symbols mean. Manipulate them algebraically as if they were numbers.Part III: Substituting numbers and solving expressionsFor each of the following, substitute the indicated values and evaluate. Include the units in each step of your work and the answer. Invert the m2 / Fg in number 4.Part IV Conversions: Use Dimensional Analysis to complete.Converting a measurement/number from one unit to another unit involves multiplying it by a series of conversion factors. Please show all your work, including all conversion factors. If you don’t know a conversion factor, look it up.1. Convert 55 km/h into m/s. 2. Convert 25 m/s into km/h3. Convert 30 km to cm. 4. Convert 65 μg to g. 5. Convert 125 ms to Ms. 6. Convert 55 Gs to s. 7. Calculate how many seconds are in an hour. 8. Calculate how many seconds are in a year. 9. Convert 5 cm2 to m210. Convert 125 m to cm11. Convert the speed of light in a vacuum 3 x 108 m/s to km/dayPart V- Geometry & Trigonometry Calculate the unknown angles.2. 3. Using the generic triangle below, Right Triangle Trigonometry and Pythagorean Theorem solve the following. Your calculator must be in degree mode. If the problem can not be completed justify why! a. ? = 55° and c = 32 m, solve for a and b. b. ? = 45° and a = 15 m/s, solve for b and c. c. b = 17.8 m and ? = 65° , solve for a and c. d. a = 250 m and b = 180 m, solve for ? and c. e. a =25 cm and c = 32 cm, solve for b and ?. f. b =104 cm and c = 65 cm, solve for a and ?.Basic trigonometry will also be very important. This means use of the three trig functions (sin,cos and tan) and their inverses (sin-1, cos-1, tan-1) will be used repeatedly. Complete the following vector break-ups (notice they all have a right angle in them) by writing in all missing angles and lengths. Show work clearly on extra blank paper.Part VI-Significant Digits All answers throughout the year will be reported with the correct number of significant digits. Part VII-Graphing: This section must be completed on graph paper. You should be able to construct a proper graph, manipulate it, analyze it and pull data from it. Graphing is an extremely important part of the AP Exam. When you make a graph:1. make sure to draw an appropriate x- and y-axis. 2. label the axes with the proper variables and with the proper units. 3. label the tick marks on each axis evenly and logically. 4. remember that a graph is titled as “Y-variable vs. X-variable” (i.e. a graph of P vs. V has P on the y-axis and V on the x-axis). A Direct Proportion is a function whose graph is a non-horizontal line that passes through the origin. y is proportional to x. y = mx where m is the slope & constant of proportionality. A Linear function has a graph that is a non-horizontal line that does not pass through the origin. A Direct Proportion is a special case of a linear function where b = 0. y = mx + b where b is the y-intercept. A Quadratic Function has a graph that is a parabola. y is proportional to x2. y = ax2 + bx + c An inverse function has a graph that is a hyperbola. y is proportional 1/x. y = k/x where k is some constant.-700087114300 ................
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