Statistical methods, Formula sheet for final exam
[Pages:5]Statistical methods, Formula sheet for final exam
Combinatorics
? Number of ways to choose k out of n objects:
n n(n - 1) ? ? ? (n - k + 1)
n!
=
=
k
k!
(n - k)!k!
Basic probability
Always true: ? P (Ac) = 1 - P (A)
? P (A B) = P (A) + P (B) - P (A B)
? P (A B) = P (A)P (B|A) ? P (Ac) = 1 - P (A)
? A, B mutually exclusive: P (A B) = P (A) + P (B)
? A, B independent: P (A B) = P (A)P (B)
? Conditional probability of A given B: P (A B)
P (A|B) = P (B)
LTP and Bayes' theorem
P (A) = P (A|B)P (B) + P (A|Bc)P (Bc)
P (A|B)P (B) P (B|A) =
P (A|B)P (B) + P (A|Bc)P (Bc)
Discrete random variables
? Pmf: p(x) = P (X = x)
Special distributions: ? X bin(n, p): p(k) = n pk(1 - p)n-k, k = 0, 1, ..., n (# of successes)
k E[X] = np ? X geom(p): p(k) = (1 - p)k-1p, k = 1, 2, ... (wait for first success)
1 E[X] =
p
Continuous random variables
? Pdf: f (x) = F (x), x R
x
? Cdf: F (x) = f (t)dt, x R
-
Special distributions:
1
? X unif [a, b]: f (x) =
, a x b (choose "randomly")
b-a
a+b E[X] =
2
? X exp(): f (x) = e-x, x 0 (memoryless)
1 E[X] =
? X N (0, 1): (x) = 1 e-x2/2, x R
2 ? X N (?, 2) : Z = X - ? N (0, 1)
Expected value
? E[X] = xxp(xk) if X is discrete with range {x1, x2, ...}
k
? E[X] = xf (x)dx if X is continuous
-
? E[g(X)] = g(xk)pX(xk)
k
? E[g(X)] = g(x)fX(x)dx -
Variance
? Var[X] = E[(X - ?)2] = E[X2] - (E[X])2
? Standard deviation: = Var[X]
Sums of random variables
? X and Y independent, a and b constants:
E[aX + bY ] = aE[X] + bE[Y ] Var[aX + bY ] = a2Var[X] + b2Var[Y ] ? X1, ..., Xn independent random variables with the same distributions, mean ? and varance 2, Sn = X1 + ... + Xn. ? E[Sn] = n? and Var[Sn] = n2 ? Central Limit Theorem: Sn is approximately N (n?, n2) and X? is approximately N (?, 2/n).
Estimators
? Unbiased: E[] =
? We want Var[] to be as small as possible
? Sample mean X? , unbiased for mean ?, Var[X? ] = 2/n
? Sample variance s2 = 1 n-1
? Standard error: Var[]
n
Xk2 - nX? 2 , unbiased for variance 2
k=1
Confidence intervals
? For ? in N (?, 2) where 2 is known:
?
=
X?
?
z
(q)
n
Use standard normal distribution, (z) = (1 + q)/2.
? For ? in N (?, 2) where 2 is unknown:
?
=
X?
?
t
s
(q)
n
Use t distribution, = 1 - (1 + q)/2, = n - 1.
? For unknown proportion p:
p(1 - p)
p=p?z
(q)
n
? For two unknown proportions p1 and p2:
p1 - p2 = p1 - p2 ? z
p1(1 - p1) + p2(1 - p2) (q)
n1
n2
In both cases, z is such that (z) = (1 + q)/2.
Estimation methods
1. The maximum likliehood estimator (MLE) maximizes the likelihood function:
n
L() = f(Xk)
k=1
To find maximum, (i) take logarithm, (ii) differentiate w.r.t. and set = 0.
2. The rth moment and rth sample moment are:
?r = E[Xr]
and
?r
=
1 Xr n
The method of moments estimator (MOME) expresses the parameter as a
function of moments, = g(?1, ..., ?r) and estimates it with the same funtion of the sample moments, = g(?1, ..., ?r). Start with the first moment, if it is not enough, go on to the second, and so on.
Linear regression
? Model: Y = a + bx + , N (0, 2) ? Observations: (x1, Y1), ..., (xn, Yn) where Yk N (a + bxk, 2) ? Notation:
? Estimators:
n
Sx =
xk,
k=1
n
Sxx =
x2k ,
k=1
n
SY = Yk
k=1
n
SxY = xkYk
k=1
b
=
nSxY - SxSY nSxx - Sx2
a = Y? - bx?
Estimated regression line: y = a + bx
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