Genetics Prac Prob #5 Blood Typing



Name _________________________________________________________________Genetics Practice Problems If a black heterozygous guinea pig is crossed with a homozygous white guinea pig with the genotype bb, what is the probability that the offspring will be white?If two hybrid tall pea plants are crossed, what is the probability that the offspring will have the tall phenotype?The different forms of a gene are called _________________._______As a result of meiosis, the number of chromosomes is reduced by half in sex cells.stays the same in sex cells.is doubled in sex cells.is quadrupled in sex cells.________The purpose of mitosis is to______________make sex cells.make gametes.create identical cells.create different cells.Both parents have genotype Rr. What genotype could the offspring have?A true-breeding tall pea plant is crossed with a true breeding short pea plant all the offspring are tall. What is the most likely genotype of the offspring assuming a single gene trait?If two white guinea pigs with genotype bb are crossed, what is the probability that the offspring will be white?_____Which of the following statements about DNA is true?DNA is single-stranded.DNA has the sugar ribose.DNA contains uracil.DNA contains thymine.Directions: Using the table and rules below, complete Table 2:Rules for writing symbolsDominant alleles are always capitalized usually by using the first letter of the trait as the symbol.The recessive allele is always represented by the small case letter of the symbol for the dominant allele.EXAMPLE: homozygous recessive for stem length x heterozygous for stem heightGenotypesParents (P1) tt x TtGametes (G1) t,t (male) T,t (female)Phenotype TraitsT = tall stem (dominant allele)t = short stem (recessive allele)F1By convention the dominant allele is written firstttTTtTttttttF1 = Filial 1 = the probable offsprings of Parents (P1)Phenotypic Ratio = 2 Tall : 2 Short stems or 2 tall stem:2 short stemGenotypic Ratio = 2 Tt : 2 tt...oor 1 Tt : 1 ttHeterozygous for stem height : Homozygous recessive for stem height.....Table 1: Mendel's Traits and Symbols for Pea PlantsTraitsDominant AlleleSymbolRecessive AlleleSymbolSeed ShapeRoundRWrinkledrSeed ColorYellowYGreenySeed Coat ColorColoredCWhitecPod ShapeSmoothSConstrictedsPod ColorGreenGYellowgStem HeightTallTShorttFlower PositionAxialATerminalaProblemsHeterozygous for seed color x Homozygous dominant for seed color (Example)Heterozygous for flower position x Heterozygous for flower positionHomozygous recessive for seed shape x Heterozygous for seed shapeHomozygous dominant for stem height x Homozygous recessive for stem heightHeterozygous seed color x Homozygous recessive for seed colorConstricted pea pod x Constricted pea podTable 2 Answers to monohybrid problemsParent GenotypesMale GametesFemale GametesPhenotypicRatioGenotypicRatio1.2.3.4.5.6.***************************************************************************PhenotypesGenotypesAAA, AOBBB, BOABABOOODirections: Given the alleles, genotypes and phenotypes for human blood typing ABO, solve the following multiple allele problems. Recall that A and B alleles are co-dominant and O is recessive. A = B > O. When figuring out problems don’t forget that there are two ways to observe the Blood Type A and Blood Type B phenotypes.What is the expected genotypic ratio among children born to a mother having the genotype AO and a father with the phenotype AB?One parent has the blood type A and the other blood type B. What are the likely genotypes of the parents if they produce children with only blood type AB?From the following blood types, determine which baby belongs to which parents. Answers to Blood Type problemsAnswer1.Genotypic Ratio:2.Parent Genotypes:3.Baby 1Baby 2Mrs. Doe -Type A Mr. Doe -Type A Mrs. Jones - Type AMr. Jones - Type ABBaby 1 - Type OBaby 2 - Type B***************************************************************************Coat color in mice is incompletely dominant. Yellow and white-colored mice are homozygous, while cream-colored mice are heterozygous. If two cream-colored mice mate, what phenotypic ratio can we expect of their offspring? Show the Punnett Square.In snapdragons, flower color is controlled by incomplete dominance. The two alleles are red (R) and white (W). The heterozygous genotype is expressed as pink.What is the phenotype of a plant with the genotype RR? ___________What is the phenotype of a plant with the genotype WW? ___________What is the phenotype of a plant with the genotype RW? ___________A pink-flowered plant is crossed with a white-flowered plant. Show the Punnett Square. What is the probability of producing a pink-flowered plant? _________%***************************************************************************"Normal" femaleXCXCNormal maleXCYCarrier femaleXCXcColor-blind MaleXcYColor-blind femaleXcXc A normal female marries a color blind male. (A) What are the chances that the offspring will be color blind if they are females? (B) What are the chances that the offspring will be color blind if they are males?A. ____________B. ____________A color-blind female marries a normal male. How many of the female offspring will be carriers of the color-blind allele?A. ____________A carrier female marries a normal male. (A) How many of the male offspring can be expected to be color-blind? A. ____________(B) How many of the male offspring can be expected to have normal vision?B. ____________(C) How many of the female offspring can be expected to be carriers?C. ____________(D) How many of the female offspring can be expected to be normal?D. ____________*************************************************************************** ................
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