Find the derivative of cotx by first principle

'= - (COS2X) / (SIN2X) Â · (1 / COS2X) = -1 / sin2x We know that the reciprocal of sin is CSC. i.e., 1 / Sin X = CSC x. So y '= -csc2x, so it proved. Derivative of the Ceramination X for the rule of the quotient, we will find the derivative of the Berte X using the rule of the quotient. This proof is the easiest among all the other methods to ... ................
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