CS502052: Enterprise Systems Development Concepts Lab 2 ...
For a JVM to be able to deserialize an object, it must be able to find the bytecode for the class. If the JVM can't find a class during the deserialization of an object, it throws a ClassNotFoundException. - Notice that the return value of readObject() is cast to an Employee reference. - The value of the SSN field was "111" when the object was serialized, but because the field is transient ... ................
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