Math 373 Chapter 5 Homework Spring 2016
Math 373 Chapter 5 Homework
Spring 2016
Chapter 5, Section 2 1. Xin has a loan for 100,000 which is being repaid with level annual payments for 5 years. The annual effective interest rate on the loan is 8%. Create an amortization table for this loan. Solution: No Solution provided.
2. Taylor has a loan of 8000 to be repaid with 5 annual payments of 2000. Determine: a. The amount of interest that Taylor will pay over the life of the loan. b. The amount of principal that Taylor will pay over the life of the loan.
Solution: a. Total interest = Total Payments ? Total Principal = 5*(2000) ? 8000 = 2000 b. Total Principal = amount of loan = 8000
3. Delaney has a loan which is being repaid with level annual payments for 12 years. The principal paid on the loan will be 10,000 and the interest paid on the loan will be 2000. Calculate the interest rate on the loan. Solution:
Total payments = Total Interest + Total Principal = 2000 + 10,000 = 12,000 Each payment = 12,000/12 payments = 1000 N= 12, PMT = -1000, PV = 10,000 CPT I/Y = 2.922854%
February 29, 2016 Copyright Jeffrey Beckley 2016
4. Chenglin has a mortgage loan which is being repaid with level payments at the end of each month for 30 years. The amount borrowed was 400,000 and the interest rate on the loan was 8% compounded monthly.
Calculate the amount of principal repaid in the 135th payment.
Solution:
N = 360, I/Y = 7/12 = 0.66666666 , PV = -400,000, CPT PMT = 2935.058
2ND Amort P1 = 135 P2 = 135 PRN = 653.81
Qvnk1 2935.058v3601351 653.81
5. Haokun borrowed money to buy a new car. Payments are made monthly. The loan has a nominal rate of interest of 15% compounded monthly. Immediately after the 18th payment, Haokun has an outstanding loan balance of 9500.
Calculate the amount of interest in the 19th payment
Solution:
Interest (OLBk1)(i)
9500
0.15 12
118.75
February 29, 2016 Copyright Jeffrey Beckley 2016
6. Daniel took a loan to buy a new couch for his apartment. He is making monthly payments and the loan has a nominal interest rate of 9% compounded monthly. Immediately after the 8th payment, Daniel still owes 800 on his loan.
The principal in his 9th payment is 90.
Determine the amount of the 9th payment.
Solution:
Interest + Principal = Total Payment
Interest
=
800
0.09 12
6
6 + 90 = 96
7. A loan is being repaid with level monthly payments. The loan has an interest rate of 4.8% compounded monthly. The principal in the 20th payment is 1000.
Calculate the principal in the 10th payment.
Solution:
1000 1
0.048 12
1020
1000(1.004)10
960.87
February 29, 2016 Copyright Jeffrey Beckley 2016
8. Avleen bought a car with a loan which Avleen is repaying with level monthly payments. The principal in the 10th payment is 511.07. The principal in the 15th payment is 542.48.
Calculate the annual effective interest rate on Avleen's loan.
Solution:
i (12) 1510
511.07 1
12
542.48
1
i (12 ) 12
5
1.061459291
1
i (12 ) 12
1.012000364
(1 i)
1
i (12 ) 12
12
(1.012000364)12
1.1538996
i
1.1538996
1
15.38996%
9. A loan is being repaid with level annual payments of 1000. The interest rate on the loan is an annual effective rate of 8%. The interest in the 5th payment is 768.29. Calculate the interest in the 10th payment. Solution: Principal in 5th: Amount of Payment less the Interest in the Payment = 1000 ? 768.29 = 231.71
Principal in 10th: 231.71(1.08)5 = 340.46since the principal is a geometric sequence
Interest in 10th: 1000 ? 340.46 = 659.54
February 29, 2016 Copyright Jeffrey Beckley 2016
10. KC has a loan which has an outstanding loan balance of 43,000 immediately after the 12th payment. The next two monthly payments are 1000 each. The interest rate on the loan is a nominal rate of 9% compounded monthly.
Calculate KC's outstanding loan balance immediately after the 14th payment.
Solution:
43,
000
0.09 12
322.50
is
interest
1000
322.50
677.50
is
the
principal
43, 000 677.50 42,322.50 is the outstanding loan balance
(42,
322.50)
0.09 12
317.42
1000
317.42
682.58
42,322.50 682.58 41, 639.92
11. A loan is being repaid with annual payments for 20 years. The principal in the 5th payment is $4236.99. The principal in the 10 payment is $5670.05.
Calculate the amount of the loan to the nearest dollar.
Solution:
4236.99(1+ i)5 = 5670.05 ? i = .06
Principal
in
kth
payment
=
Qvnk 1
Q
1 1.06
2051
4236.99
Q
10, 763.44
N=20, I/Y = 6, PMT=-10763.44, CPT PV = 123,455.81
February 29, 2016 Copyright Jeffrey Beckley 2016
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