Shape and measurement
Chapter 10
10
Shape and measurement
What is Pythagoras' theorem? How do we use Pythagoras' theorem? How do we find the perimeter of a shape? How do we find the area of a shape? What is a composite shape? How do we find the volume of a shape? How do we find the surface area of a shape? What does it mean when we say that two figures are similar? What are the tests for similarity for triangles? How do we know whether two solids are similar?
Cambridge Senior Maths AC/VCE General Maths 1&2
ISBN 978-1-107-56755-9
? Jones et al. 2016
Cambridge University Press
Photocopying is restricted under law and this material must not be transferred to another party.
470 Chapter 10 Shape and measurement
Introduction
The geometry chapter covers perimeter and area of 2D shapes, and surface area and volume of 3D solids. It also covers similarity within 2D shapes and 3D solids.
10A Pythagoras' theorem
Pythagoras' theorem is a relationship connecting the side lengths of a right-angled triangle. In a right-angled triangle, the side opposite the right angle is called the hypotenuse. The hypotenuse is always the longest side of a right-angled triangle.
Pythagoras' theorem
Pythagoras' theorem states that, for any right-angled triangle, the sum of the areas of the squares of the two shorter sides (a and b) equals the area of the square of the hypotenuse (c).
c2 = a2 + b2
Pythagoras' theorem can be used to find the length of the hypotenuse in a right-angled triangle.
hypotenuse
a2 a
c2 = a2 + b2 c
b b2
Example 1 Using Pythagoras' theorem to calculate the length of the hypotenuse
Calculate the length of the hypotenuse in the triangle opposite,
correct to two decimal places.
4 cm
c cm
10 cm
Solution
1 Write Pythagoras' theorem.
c2 = a2 + b2
2 Substitute known values. 3 Take the square root of both sides, then
evaluate.
4 Write your answer correct to two decimal places, with correct units.
c2 = 102 + 42
c = 102 + 42
= 10.770 . . . The length of the hypotenuse is 10.77 cm, correct to two decimal places.
Hint: To ensure that you get a decimal answer, set your calculator to approximate or decimal mode. (See the Appendix.)
Cambridge Senior Maths AC/VCE General Maths 1&2
ISBN 978-1-107-56755-9
? Jones et al. 2016
Cambridge University Press
Photocopying is restricted under law and this material must not be transferred to another party.
10A Pythagoras' theorem 471
Pythagoras' theorem can also be rearranged to find sides other than the hypotenuse.
Example 2 Using Pythagoras' theorem to calculate the length of an unknown side
in a right-angled triangle
Calculate the length of the unknown side, x, in the triangle opposite, correct to one decimal place.
4.7 mm
x mm 11 mm
Solution
1 Write Pythagoras' theorem. 2 Substitute known values and the given
variable. 3 Rearrange the formula to make x the
subject, then evaluate. 4 Write your answer correct to one
decimal place, with correct units.
a2 + b2 = c2 x2 + 4.72 = 112
x = 112 - 4.72
= 9.945 . . . The length of x is 9.9 mm, correct to one decimal place.
Pythagoras' theorem can be used to solve many practical problems.
Example 3 Using Pythagoras' theorem to solve a practical problem
A helicopter hovers at a height of 150 m above the ground and is a horizontal distance of 220 m from a landing pad. Find the direct distance of the helicopter from the landing pad, correct to two decimal places.
Solution 1 Draw a diagram to show which
distance is to be found.
c m
150 m
2 Write Pythagoras' theorem. 3 Substitute known values.
4 Take the square root of both sides, then evaluate.
5 Write your answer correct to two decimal places, with correct units.
220 m c2 = a2 + b2 c2 = 1502 + 2202
c = 1502 + 2202
= 266.270 . . .
The helicopter is 266.27 m from the landing pad, correct to two decimal places.
Cambridge Senior Maths AC/VCE General Maths 1&2
ISBN 978-1-107-56755-9
? Jones et al. 2016
Cambridge University Press
Photocopying is restricted under law and this material must not be transferred to another party.
472 Chapter 10 Shape and measurement
10A
Exercise 10A
Skillsheet 1 Find the length of the unknown side in each of these triangles, correct to one decimal place.
Example 1, 2
a 2.5 cm
c cm
b
54 cm
4.2 cm
63.2 cm
h cm
c
d
3.3 mm
26 mm
x mm
y mm
2.3mm
10 mm
e
15.7 mm
22.3 mm
k mm
g
4.5 cm
v cm
4.5 cm i
19.8 m t m
12.4 m
f x cm
3.9 cm
6.3 cm h
a mm
158 mm
212 mm
Cambridge Senior Maths AC/VCE General Maths 1&2
ISBN 978-1-107-56755-9
? Jones et al. 2016
Cambridge University Press
Photocopying is restricted under law and this material must not be transferred to another party.
10A
10A Pythagoras' theorem 473
Applications of Pythagoras' theorem
Example 3 2 A farm gate that is 1.4 m high is supported by a diagonal bar of length 3.2 m. Find the width of the gate, correct to one decimal place.
3 A ladder rests against a brick wall as shown in the diagram on the right. The base of the ladder is 1.5 m from the wall, and the top reaches 3.5 m up the wall. Find the length of the ladder, correct to one decimal place.
3.2 m
1.4 m
3.5 m
4 The base of a ladder leaning against a wall is 1.5 m from the base of the wall. If the ladder is 5.5 m long, find how high the top of the ladder is from the ground, correct to one decimal place.
1.5 m 5.5 m
1.5 m
5 A ship sails 42 km due west and then 25 km due
N
south. How far is the ship from its starting point?
(Answer correct to two decimal places.)
W
42 O
E
25
S
6 A yacht sails 12 km due east and then 9 km due north. How far is it from its starting point?
7 A hiker walks 10 km due west and then 8 km due north. How far is she from her starting point? (Answer correct to two decimal places.)
8 In a triangle ABC, there is a right angle at B. AB is 12 cm and BC is 16 cm. Find the length of AC.
A 12 cm
B
16 cm
C
Cambridge Senior Maths AC/VCE General Maths 1&2
ISBN 978-1-107-56755-9
? Jones et al. 2016
Cambridge University Press
Photocopying is restricted under law and this material must not be transferred to another party.
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