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(b) The empirical formula is the ratio (moles iodine) / (moles Cu). OR (moles Cu) / (moles iodine). (c) (1) Unreacted I2 would make the apparent mass of compound and the iodine too high. Thus, the I:Cu ratio in the empirical formula would be too high. (2) If some compound flaked off, the mass of compound (and the I2) would be too low. ................
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