Conversion molality to molarity - Just Only
[Pages:1]Conversion from Molality to Molarity
Problem: Find the molarity of 21.4 m HF. This aqueous solution has a density of 1.101 g/mL.
Step 1. Make an assumption.
Assume you have 1 kg of solvent (water). This is a very important step and the amount of solution is not given but you need to have a specific quantity to do the calculations and one kilogram is the best assumption.
Step 2. Find the total mass of HF (solute).
21.4 m means 21.4 moles /kg solvent (water). 21.4 X 20.01 g/mole = 428.21 grams HF.
Step 3. Calculate the total grams of the solution.
1000 grams solvent (water) + 428.21 grams HF = 1428.21 grams solution.
Step 4. Calculate the volume (Liters) of solution.
1428.21 grams X 1mL/1.101 grams (density) = 1297.19 mL = 1.29719 L
Step 5. Calculate the molarity.
21.4 moles solute / 1.29719 L = 16.5 M HF
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