Richland Parish School Board



574 + 869 = n

Method #1:

Step 1 Step 2 Step 3 Step 4

574 574 574 574

+869 +869 +869 +869

1,300 1,300 1,300 1,300

130 130 130

13 + 13

1,443

Method #2:

Step 1 Step 2 Step 3 Step 4

574 574 574 574

+869 +869 +869 +869

13 13 13 13

130 130 130

1,300 +1,300

1,443

Method # 3:

Step 1 Step 2 Step 3

1 1 1 1 1

574 574 574

+869 +869 +869

3 43 1,443

1. 9,491 + 4,028 = n

a) n = ____________

b) Change the 0 hundreds in the 4,028 to 6 hundreds. Solve the new problem using the standard algorithm:

c) n = ____________

d) Explain how the change impacted the sum:

____________________________________

____________________________________

____________________________________

____________________________________

____________________________________

____________________________________

____________________________________

2. 8,507 - 3,592 = n

a) n = ____________

b) Change the 5 hundreds in 8,507

to 6 hundreds. Solve the new problem using the standard algorithm:

c) n = ____________

d) Explain how the change impacted the sum:

____________________________________

____________________________________

____________________________________

____________________________________

____________________________________

____________________________________

____________________________________

1. 9,491 + 4,028 = n

1

9,491

+ 4,028

13,519

a) n = 13,519

b) Change the 0 hundreds in 4,028 to 6 hundreds. Solve the new problem using the standard algorithm:

1 1

9,491

+ 4,628

14,119

c) n =14,119

d) Explain how the change impacted the sum:

By changing the 0 hundreds in 4,028 into 6

hundreds, it made me have to place one

thousand over the thousands place because I

now had 11 hundreds instead of 5 hundred.

It changed my answer by 6 hundreds.

2. 8,507 - 3,592 = n

7 14 10

8, 5 0 7

- 3, 5 9 2

4, 9 1 5

a) n = 4,915

b) Change the 5 hundreds in 8,507

to 6 hundreds. Solve the new problem using the standard algorithm:

5 10

8, 6 0 7

- 3, 5 9 2

5, 0 1 5

c) n = 5,015

d) Explain how the change impacted the sum:

By changing the 5 hundreds in 8,507 into 6

hundreds, it made me not have to exchange

1 thousand from 8 thousand to make 10

hundreds. It changed by answer by 1

hundred.

1) 539

+781__

8,349

Explain the mistake:

____________________________________

____________________________________

____________________________________

2) 719

+ 675

1,384

Explain the mistake:

____________________________________

____________________________________

____________________________________

3) 2,418

+ 5,606

71,014

Explain the mistake:

____________________________________

____________________________________

____________________________________

4) 6,347

+ 5,286

11,533

Explain the mistake:

____________________________________

____________________________________

____________________________________

5) 341

- 274

133

Explain the mistake:

____________________________________

____________________________________

____________________________________

6) 4,395

- 2,178

2,227

Explain the mistake:

____________________________________

____________________________________

____________________________________

7) 452

- 303_

3,422

Explain the mistake:

____________________________________

____________________________________

____________________________________

8) 8,715

- 5,627

3,078

Explain the mistake:

____________________________________

____________________________________

____________________________________

1) 539

+781__

8,349

Explain the mistake:

Since 781 is not lined up with 539 based on

place value, the values being added are not

correct.

2) 719

+ 675

1,384

Explain the mistake:

Since 9 + 5 = 14, it should be 10 + 10 + 70

= 90 in the tens column instead of only 10 +

70 = 80.

3) 2,418

+ 5,606

71,014

Explain the mistake:

Since 400 + 600 = 1,000, the 1 thousand

should be added to the other thousands, not placed in the sum. 1 thousand + 2 thousands + 5 thousands is not 71 thousands.

4) 6,347

+ 5,286

11,533

Explain the mistake:

Since 7 + 6 = 13 and the 1 ten should be placed above the tens place, 10 + 40 + 80 = 130. The 1 hundred should be placed above the hundreds place, 100 + 300 + 200 = 600.

5) 341

- 274

133

Explain the mistake:

It should be 1 – 4, not 4 – 1 in the ones column and 40 – 70, not 70 – 40 in the tens column.

6) 4,395

- 2,178

2,227

Explain the mistake:

90 becomes 80 so that 1 ten can be added to 5 ones in order to subtract 15 – 8, the tens column should become 80 – 70 instead of 90 – 70.

7) 452

- 303_

3,422

Explain the mistake:

Since 452 is not lined up with 303 based on place value, the difference is not correct.

8) 8,715

- 5,627

3,078

Explain the mistake:

Since 1 ten was added to 5 ones so that 15 – 7 = 8, there are no longer any tens. 700 becomes 600 so that 10 tens can be added to the tens column so 100 – 20 = 80, not 70.

Name: Date:

1. 3,910 Time:

+ 7,298 _______

2. 8,726 Time:

+ 6,515 _______

3. 2,083 Time:

+ 3,619 _______

4. 5,463 Time:

+ 9,204 _______

5. 4,199 Time:

+ 7,085 _______

1. 8,017 Time:

- 3,189 _______

2. 9,809 Time:

- 7,920 _______

3. 8,039 Time:

- 4,337 _______

4. 7,322 Time:

- 6,103 _______

5. 4,000 Time:

- 2,194 _______

Name:

1 1

1. 3,910 Time:

+ 7,298 _______

11,208

1 1

2. 8,726 Time:

+ 6,515 _______

15,241

1 1

3. 2,083 Time:

+ 3,619 _______

5,702

4. 5,463 Time:

+ 9,204 _______

14,667

1 1

5. 4,199 Time:

+ 7,085 _______

11,284

Date: ____________

9 10

7 10 0 17

1. 8, 0 1 7 Time:

- 3, 1 8 9 _______

4, 8 2 8

6

8 7 10

2. 9, 8 0 9 Time:

- 7, 9 2 0 _______

1, 8 8 9

7 10

3. 8, 0 3 9 Time:

- 4 ,3 3 7 _______

3, 7 0 2

1 12

4. 7, 3 2 2 Time:

- 6, 1 0 3 _______

1, 2 1 9

9 9

3 10 10 10

5. 4, 0 0 0 Time:

- 2, 1 9 4 _____

1, 8 0 6

1. 28 children were playing on the playground in the morning. In the afternoon, 15 more children came. 9 children left after that. How many children are at the park at the end of the day?

2. The cafeteria has 2,856 cartons of chocolate milk. There are 4,793 cartons of chocolate and white milk altogether. How many fewer cartons of white milk than chocolate milk are there?

3. Of the students at Willie Mays Elementary School, 159 of the 234 children are wearing shorts. How many more students are wearing shorts than are not wearing shorts?

4. This fall, Carol read 275 pages in her science textbook. In the winter, she read 83 pages before winter break and 99 pages after winter break. How many pages will she have to read in the spring in order for her to read all 576 pages?

5. The students in the third, fourth, and fifth grades scored 357 A’s, 105 B’s, and 67 C’s. How many more A’s than B’s and C’s did the students have?

1. 28 children were playing on the playground in the morning. In the afternoon, 15 more children came. 9 children left after that. How many children are at the park at the end of the day?

28 + 15 = 43; There were 43 children in the afternoon.

43 – 9 = 34; There were 34 children at the end of the day.

2. The cafeteria has 2,856 cartons of chocolate milk. There are 4,793 cartons of chocolate and white milk altogether. How many fewer cartons of white milk than chocolate milk are there?

4,793 – 2,856 = 1,937; There are 1,937 cartons of white milk.

2,856 – 1,937 = 919; There are 919 fewer cartons of white milk than chocolate milk.

3. Of the students at Willie Mays Elementary School, 159 of the 234 children are wearing shorts. How many more students are wearing shorts than are not wearing shorts?

234 – 159 = 75; Seventy-five students not wearing shorts

159 – 75 = 84; Eighty-four more students are wearing shorts than not wearing shorts

4. This fall, Carol read 275 pages in her science textbook. In the winter, she read 83 pages before winter break and 99 pages after winter break. How many pages will she have to read in the spring in order for her to read all 576 pages?

275 + 83 + 99 = 457; Carol has read 457 pages.

576 – 457 = 119; She will need to read 119 pages during the spring.

5. The students in the third, fourth, and fifth grades scored 357 A’s, 105 B’s, and 67 C’s. How many more A’s than B’s and C’s did the students have?

105 + 67 = 172; One hundred seventy-two students scored B’s and C’s.

357 – 172 = 185; One hundred eighty-five more students scored A’s than B’s and C’s combined.

39 × 82 = n

Method # 1:

Step 1 Step 2 Step 3 Step 4 Step 5

39 39 39 39 39

× 82 × 82 × 82 × 82 × 82

18 18 18 18 18

60 60 60 60

720 720 720

2,400 + 2,400

3,198

Method #2:

Step 1 Step 2 Step 3 Step 4 Step 5

7 7 7

1 1 1 1 1

39 39 39 39 39

× 82 × 82 × 82 × 82 × 82

8 78 78 78 78

20 3,120 + 3,120

3,198

Solve the division problems below.

1. 40 ( 8 =

2. 41 ( 8 =

3. 42 ( 8 =

4. 43 ( 8 =

5. 44 ( 8 =

6. 45 ( 8 =

7. 46 ( 8 =

8. 47 ( 8 =

9. 48 ( 8 =

Predict the remainders for the following division problems.

10. 24 ( 6 =

11. 25 ( 6 =

12. 26 ( 6 =

13. 27 ( 6 =

14. 28 ( 6 =

15. 29 ( 6 =

16. 30 ( 6 =

17. 31 ( 6 =

49 ( 6 = n

1. The Atkinson Fencing Company has 49 feet of fencing. They need to make 6-foot sections of fencing for a yard. How many sections of fencing can they make?

2. The fourth grade class is on a field trip to an amusement park. 49 students are in line to ride the first rollercoaster. Each rollercoaster car can fit 6 people. How many rollercoaster cars do they need so that everyone can ride?

3. 49 students want to play in the basketball tournament this weekend. If each team can only have 6 students, how many students cannot play on a team?

356 ( 9 = n

4. Isaac Newton Elementary is having a festival to celebrate their 50th anniversary. 356 students want to ride the Spinning Wheel ride. If only 9 students can go on the ride at one time, how many times must the Spinning Wheel ride take a group of students for every student to ride it at least once?

5. In the beginning of the school year, the 4th grade teacher at Jackie Robinson Elementary bought 356 pencils. If he gave 9 pencils to each of his students, how many students received pencils?

6. There are 356 students who want to try out for one of the 9 dance teams. If each team has to have the same number of students, how many students cannot be on a team?

49 ( 6 = n

1. The Atkinson Fencing Company has 49 feet of fencing. They need to make 6-foot sections of fencing for a yard. How many sections of fencing can they make?

49 ( 6 = 8 r 1. They can make 8 sections of fencing.

2. The fourth grade class is on a field trip to an amusement park. 49 students are in line to ride the first rollercoaster. Each rollercoaster car can fit 6 people. How many rollercoaster cars do they need so that everyone can ride?

49 ( 6 = 8 r 1. They need 9 rollercoaster cars.

3. 49 students want to play in the basketball tournament this weekend. If each team can only have 6 students, how many students cannot play on a team?

49 ( 6 = 8 r 1. 1 student cannot play on a team.

356 ( 9 = n

4. Isaac Newton Elementary is having a festival to celebrate their 50th anniversary. 356 students want to ride the Spinning Wheel ride. If only 9 students can go on the ride at one time, how many times must the Spinning Wheel ride take a group of students for every student to ride it at least once?

356 ( 9 = 39 r 5. The Spinning Wheel ride will take 40 groups of students so that every student can ride the ride at least once.

5. In the beginning of the school year, the 4th grade teacher at Jackie Robinson Elementary bought 356 pencils. If he gave 9 pencils to each of his students, how many students received pencils?

356 ( 9 = 39 r 5. 39 students will receive pencils.

6. There are 356 students who want to try out for one of the 9 dance teams. If each team has to have the same number of students, how many students cannot be on a team?

356 ( 9 = 39 r 5. 5 students cannot be on a team.

For 4-Digit by 1-Digit Multiplication:

For 2-Digit by 2-Digit Multiplication:

For 4-Digit by 1-Digit Division:

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