Math 123c test



Math 260 Log and Exp (sect 33-39)Log-exp ConversionsWrite a–1/3 = QUOTE in log form Write Ln(A/P) = –rt in the exponential form Convert the form then solve the following equations without the calculator. logx(9) = –1/2 – 3 = log 2 (1 – 2x) Log (x2 – 21) = 2 x = 10 1 + 2 LOG (5) Assemble the expressions 2* LOG (x) – 5LOG (x + 1) + ? LOG (x – 2) into one Log. Disassemble Ln QUOTE in terms of sums and differences logs as much as possible:(Solving Numerically Linear Log-exp Equations)Solve. Give the exact answer and the approximate answer to three significant digits. 5*LOG (4x + 1) – 2 = 7 12.4 = 2.8 + 1.1* 10–0.09t 5* e4x+1 – 2 = 7 12.4 = 2.8 + ln(– 0.09t) 5 + 6*107x = 8 2 + 5*log(2x – 3) = 11 Solve without the calculator:log 3 (x + 5) + log 3 (x – 1) = 3 4*87x + 1 = QUOTE QUOTE log 3 (x + 5) = 3 + log 3 (x – 1) 4/87x + 1 = QUOTE QUOTE x = 10 1 + 2 LOG (5) 2 = log 3 (37x + 1)(PertA) Continuous compound P*ert = A, With interest rate r = 4.5%, what is the principle P needed in order for it to become $10,000 after 10 years?What’s interest rate r if the same principle P becomes $10,000 after only 5 years?If the interest rate r = 15%, how long will it take for the same principle to becomes $10,000? ................
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