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Example 10 Find the average value of sin2x cos2x on the interval [O, 2771. Solution By definition, the average value is the integral divided by the length of the interval: By Example 2, Jsin2x cos2x dx = (x/8) - (sin4x/32) + C. Thus so the average value is (1/2n) - 77/4 = 1/8. ki Exercises for Section 10.1 ................
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