Chapter 1 Trigonometry 1 TRIGONOMETRY - CIMT
[Pages:32]1 TRIGONOMETRY
Objectives
After studying this chapter you should ? be able to handle with confidence a wide range of
trigonometric identities; ? be able to express linear combinations of sine and cosine in
any of the forms Rsin( ? ) or R cos( ? ) ;
? know how to find general solutions of trigonometric equations; ? be familiar with inverse trigonometric functions and the
associated calculus.
1.0 Introduction
In the first Pure Mathematics book in this series, you will have encountered many of the elementary results concerning the trigonometric functions. These will, by and large, be taken as read in this chapter. However, in the first few sections there is some degree of overlap between the two books: this will be good revision for you.
1.1 Sum and product formulae
You may recall that
sin( A + B) = sin A cos B + cos Asin B sin( A - B) = sin A cos B - cos Asin B
Adding these two equations gives
sin( A + B) + sin( A - B) = 2 sin A cos B
(1)
Let C = A + B and D = A - B,
then C + D = 2 A and C - D = 2B. Hence
A= C+D, B= C-D
2
2
and (1) can be written as
Chapter 1 Trigonometry
1
Chapter 1 Trigonometry
sin
C
+
sin
D
=
2
sin
C
+ 2
D
cos
C
- 2
D
This is more easily remembered as
'sine plus sine = twice sine(half the sum) cos(half the difference)'
Activity 1
In a similar way to above, derive the formulae for (a) sin C - sin D (b) cos C + cos D (c) cos C - cos D By reversing these formulae, write down further formulae for (a) 2 sin E cos F (b) 2 cos E cos F (c) 2 sin E sin F
Example
Show that cos 59? +sin 59? = 2 cos14? .
Solution Firstly,
sin 59? = cos 31? , since sin = cos(90 - )
So
LHS = cos 59? + cos 31?
=
2
cos
59
+ 2
31
cos
59
- 2
31
= 2 cos 45? ? cos14?
= 2 ? 2 cos14? 2
= 2 cos14? = RHS
Example Prove that sin x + sin 2x + sin 3x = sin 2x(1 + 2 cos x).
Solution
LHS = sin 2x + (sin x + sin 3x)
=
sin
2
x
+
2
sin
3x + 2
x
cos
3x - 2
x
= sin 2x + 2 sin 2x cos x
= sin 2x(1 + 2 cos x)
2
Example
Write cos 4x cos x - sin 6x sin 3x as a product of terms.
Solution Now
and
cos 4x cos x
= 1 {cos(4x + x) + cos(4x - x)}
2
= 1 cos 5x + 1 cos 3x
2
2
sin 6x sin 3x = 1 {cos(6x - 3x) - cos(6x + 3x)}
2
= 1 cos 3x - 1 cos 9x
2
2
Thus,
LHS = 1 cos 5x + 1 cos 3x - 1 cos 3x + 1 cos 9x
2
2
2
2
= 1 (cos 5x + cos 9x) 2
=
1 2
?
2 cos
5x
+ 2
9x
cos
5x
- 2
9x
= cos 7x cos 2x
The sum formulae are given by
sin
A + sin B =
2 sin
A+ 2
B
cos
A- 2
B
sin A - sin B = 2 cos
A+ B 2
sin
A
- 2
B
cos
A
+
cos
B
=
2
cos
A
+ 2
B
cos
A
- 2
B
cos
A
-
cos
B
=
?2 sin
A
+ 2
B
sin
A
- 2
B
and the product formulae by
sin A cos B = 1 (sin( A + B) + sin( A - B)) 2
cos A cos B = 1 (cos( A + B) + cos( A - B)) 2
sin Asin B = 1 (cos( A - B) - cos( A + B)) 2
Chapter 1 Trigonometry
3
Chapter 1 Trigonometry
Exercise 1A
1. Write the following expressions as products:
(a) cos5x - cos3x
(b) sin11x - sin 7x
(c) cos2 x + cos9x
(d) sin 3x + sin13x
(e)
cos 2 15
+
cos
14 15
+
cos
4 15
+
cos
8 15
(f) sin 40? + sin 50? + sin 60?
(g) cos114? + sin 24? 2. Evaluate in rational/surd form
sin75? + sin15? 3. Write the following expressions as sums or
differences: (a) 2 cos 7x cos5x
(b)
2 cos
1 2
x cos
5x 2
(c)
2
sin
4
-
3
cos
4
+
(d) 2sin165?cos105?
4. Establish the following identities: (a) cos - cos3 = 4sin2 cos (b) sin 6 x + sin 4 x - sin 2 x = 4 cos3x sin 2 x cos x
(c) 2sin 4 A + sin 6 A + sin 2 A = cot2 A 2sin 4 A - sin 6 A - sin 2 A
(d)
sin( A cos( A
+ +
B) B)
+ +
sin( A - B) cos( A - B)
=
tan
A
(e) cos( + 30?) + cos( + 60?) = 1 - tan sin( + 30?) + sin( + 60?) 1 + tan
5. Write cos12 x + cos6 x + cos 4 x + cos2 x as a product of terms.
6. Express cos3x cos x - cos 7x cos5x as a product of terms.
1.2 Linear combinations of sin and cos
Expressions of the form a cos + b sin , for constants a and b, involve two trig functions which, on the surface, makes them difficult to handle. After working through the following activity, however, you should be able to see that such expressions (called linear combinations of sin and cos ? linear since they involve no squared terms or higher powers) can be written as a single trig function. By re-writing them in this way you can deduce many results from the elementary properties of the sine or cosine function, and solve equations, without having to resort to more complicated techniques.
For this next activity you will find it very useful to have a graph plotting facility. Remember, you will be working in radians.
Activity 2
Sketch the graph of a function of the form y = a sin x + b cos x
(where a and b are constants) in the range - x . 4
From the graph, you must identify the amplitude of the function and the x-coordinates of
(i) the crossing point on the x-axis nearest to the origin, and (ii) the first maximum of the function
as accurately as you can.
An example has been done for you; for y = sin x + cos x , you can see that amplitude R 1. 4
crossing
point
nearest
to
the
origin
O
at
x
=
=
?
4
-
maximum
occurs
at
x
=
=
4
Try these for yourself :
(a) y = 3sin x + 4 cos x (c) y = 9 cos x + 12 sin x (e) y = 2 sin x + 5 cos x
(b) y = 12 cos x - 5sin x (d) y = 15sin x - 8 cos x (f) y = 3cos x - 2 sin x
In each case, make a note of
R, the amplitude; , the crossing point nearest to O; , the x -coordinate of the maximum.
Chapter 1 Trigonometry
y R 1
-1
x
In each example above, you should have noticed that the curve is itself a sine/cosine 'wave'. These can be obtained from the curves of either y = sin x or y = cos x by means of two simple transformations (taken in any order).
1. A stretch parallel to the y-axis by a factor of R, the amplitude, and
2. A translation parallel to the x-axis by either or (depending on whether you wish to start with sin x or cos x as the original function).
Consider, for example y = sin x + cos x. This can be written in the
form y = Rsin(x + ), since
Rsin(x + ) = R{sin x cos + cos x sin }
= R cos sin x + Rsin cos x
The R(> 0) and should be chosen so that this expression is the
same as sin x + cos x.
5
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