Review: Balancing Redox Reactions - California State University, Los ...
Cu2+(aq) + 2 e-o→ Cu(s) E = .337 V Ni(s) → Ni2+(aq) + 2 e-Eo = .25 V Step 3: add half reactions to get net reaction, and add potentials to get net cell potential Cu2+(aq) + Ni(s) → Cu(s) + Ni2+(aq) Eo = .59 V Because Eo for the cell is positive, the reaction proceeds as written Electrochemical Cells Example: Determine Eo for a Mg2 ... ................
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