Math Assesment - Chemeketa Community College

(bcd)b + c = d (the second equation plugged into the first) b2cd + c = d. b2cd = d – c. b2 = (d – c)/(cd) b2 = 1/c – 1/d (this simplifies the expression) b = sqrt(1/c – 1/d) Now plug the above solution into the second equation solved for a. a = sqrt(1/c – 1/d)cd Vector Arithmetic. You must be able to … ................
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