Comparisons Among Several Samples (Analysis of Variance ...
Variance=10*10+5*5=125, so standard deviation=sqrt(125)=11.2 lbs. It does seem likely that the weights of the male and the female partner would be independent. If the correlation between . X. and . Y. equals 0.77, what is the standard deviation of the random variable . W. Variance = 10*10+5*5 + 2 * 0.77 * 10 * 5=202, so standard deviation ... ................
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