Mark Scheme (Results)

[Pages:14]Mark Scheme (Results)

Pearson Edexcel

Additional Sample Assessment Materials GCSE 9-1 Combined Science

Paper 6: Physics 1SC0/2PH

First examination 2018

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General Marking Guidance

All candidates must receive the same treatment. Examiners must mark the first candidate in exactly the same way as they mark the last.

Mark schemes should be applied positively. Candidates must be rewarded for what they have shown they can do rather than penalised for omissions.

Examiners should mark according to the mark scheme not according to their perception of where the grade boundaries may lie.

There is no ceiling on achievement. All marks on the mark scheme should be used appropriately.

All the marks on the mark scheme are designed to be awarded. Examiners should always award full marks if deserved, i.e. if the answer matches the mark scheme. Examiners should also be prepared to award zero marks if the candidate's response is not worthy of credit according to the mark scheme.

Where some judgement is required, mark schemes will provide the principles by which marks will be awarded and exemplification may be limited.

When examiners are in doubt regarding the application of the mark scheme to a candidate's response, the team leader must be consulted.

Crossed out work should be marked UNLESS the candidate has replaced it with an alternative response.

Pearson Edexcel Leve1 / Level 2 GCSE (9-1) in Physics

1SC_1PH Mark Scheme

Question number 1 (a)

Answer

Additional guidance

An answer that combines the following points of understanding to provide a logical description:

Mark (2)

named force (acting at a distance) e.g.

(1)

magnetic

situation (1)

force between two (magnetic) poles

Question number 1 (b)(i)

Answer

rearrangement of work = force ? distance to give distance = work ? force (1)

substitution and evaluation (1) 18 (m)

Question number 1 (b)(ii)

Answer 2700 (J)

Additional guidance Mark (2)

seeing 2700 ? 150

Award full marks for correct answer without working

Mark (1)

Question number 1 (b)(iii)

Answer

rearrangement of KE = ? mv2

v = (2 ? KE ? m) (1)

substitution and evaluation (1)

19 (m/s)

Additional guidance Mark

(2)

v = (2 ? 2700 ? 15) v2 = (2 ? 2700 ? 15)

allow answers that round to 19

award full marks for correct answer without working

allow alternative route using v2 - u2 = 2ax for full marks

Question number 1 (c)

Answer

An answer that combines points of interpretation/evaluation to provide a logical description:

Additional guidance

Mark (2)

efficiency increases (at first) (1)

to maximum efficiency (for mass e.g. decreases for

of about 25 kg) (1)

larger masses

(Total for Question 1 = 9 marks)

Question number 2 (a)

Answer substitution into P = V ? I (1) 2600 = 230 ? I

Additional guidance

Substitution and rearrangement in either order

rearrangement (1)

I = P ? V

I = 2600 ? 230 for 2 marks

evaluation (1)

11 (A)

allow answers that round to 11

award full marks for correct answer without working

allow I = 2.6 ? 230 for 1 mark allow 0.011 (A) for 2 marks max

if no other marks scored, award 1 mark for 2.6 kW = 2600 W

Mark (3)

Question Answer number

2 (b)(i) either power = (current)2 ? resistance OR

P = I2 ? R

Mark (1)

Question number 2 (b)(ii)

Answer

substitution into P = I2 ? R (1)

55 = 4.42 ? R

rearrangement (1)

R = P ? I2

Additional guidance

Substitution and rearrangement in either order

Mark (3)

R = 55 ? 4.42 for 2 marks

evaluation (1) 2.8 ()

allow answers that round to 2.8

award full marks for correct answer without working

allow alternative route V = P ? I = 55 ? 4.4

then R = V ? I = 12.5 ? 4.4

(Total for Question 2 = 7 marks)

Question number

3(a)

Answer

An answer that combines points of interpretation/evaluation to provide a logical description: Use of lubrication / oil (1) To reduce friction (between parts) (1)

Mark (2)

Question number 3(b)

Answer

C a javelin moves through the air after leaving an athlete's hand

Mark (1)

Question number 3(c)

Answer

An explanation identifying the fact that the forces shown are acting on two different bodies / they are not acting on the same body (1)

Mark (1)

Question number 3(d)(ii)

Answer

drawing shows a completed triangle or parallelogram (1)

Additional guidance

Mark (2)

Evaluation 3.6 N (1)

?0.2 N may be calculated using Pythagoras theorem

Question number 3(d)(i)

Answer

two vector arrows at rights angles representing the forces (1)

two vector arrows in proportion (1) examples:

Mark (2)

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