Chapter 01 - Measurement of Interest
Chapter 01 - Measurement of Interest
Section 1.1 - Introduction
Definition: Interest is the compensation that a borrower of capital pays to a lender of capital for its use.
Definition: The principal is the amount of money initially borrowed. This money accumulates over time. The difference between the initial amount and the amount returned at the end of the period is called interest.
Section 1.2 - Basics
Definition: The accumulation function, a(t), describes the accumulated value at time t of initial investment of 1.
1-1
Properties of the accumulation function: (1) a(0) = 1 (2) a(t) is generally increasing function of time. (3) If interest accrues continuously then a(t) will be a continuous
function.
Definition: The amount function, A(t), gives the accumulated value of an initial investment of k at time t, i.e.
A(t) = ka(t). It follows that:
A(0) = k , and the interest earned during the nth period from the date of investment is:
In = A(n) - A(n - 1) for n = 1, 2, ? ? ? .
1-2
Section 1.3 - Rates of Interest
Definition: The effective rate of interest, i, is the amount that 1 invested at the beginning of the period will earn during the period when the interest is paid at the end of the period.
That is,
i = a(1) - a(0) or (1 + i) = a(1).
The quantity i is always a decimal value even though it is often expressed as a percent, i.e.
6% interest
i = .06
Note that
A(1) - A(0)
i = a(1) - a(0) =
=
I1
A(0)
A(0)
1-3
The effective rate of interest is the interest earned in the period divided by the principal at the beginning of the period.
Thus by extension,
in
=
A(n) - A(n - A(n - 1)
1)
=
In A(n -
1)
is the effective rate of interest during the nth period from the date of investment. Also,
a(n) - a(n - 1)
in = a(n - 1)
for n = 1, 2, ? ? ? .
Example: Consider the accumulation function
a(t) = (.05)t2 + 1. Here a(0) = 1 and
i1 = a(1) - a(0) = .05 + 1 - 1 = .05. is the effective interest rate for period one.
1-4
For the nth period, the effective interest rate is:
a(n) - a(n - 1)
in =
a(n - 1)
(.05)(n)2 + 1 - [(.05)(n - 1)2 + 1]
=
(.05)(n - 1)2 + 1
(.10)n - (.05) = (.05)(n - 1)2 + 1
n in 1 .05 2 .143 3 .208
If $100 is invested, how much interest will be earned over three
periods? Ans = 100[a(3) - a(0)] = 100[(.05)(3)2 + 1 - 1] = $45.
1-5
Section 1.4 - Simple Interest
Under simple interest,
a(t) = 1 + (n - 1)i for n - 1 t < n and n = 1, 2, 3, ? ? ?
The effective rate of interest for the nth period is
a(n) - a(n - 1)
in =
a(n - 1)
(1 + in) - (1 + i(n - 1)) =
1 + i(n - 1)
=
i .
1 + i(n - 1)
This is a decreasing function of n.
Why is it decreasing?
1-6
Answer: The same amount of interest is credited to the account for each period. Since the amount in the account is increasing, the effective rate is
i
constant
=
a(n - 1) increasing function
which will be a decreasing function. Simple interest can be extended
to partial periods by letting
a(t) = 1 + it for all t 0.
This extension is justified when interest will be paid for partial periods and accumulation increments have an additive nature.
1-7
Additive accumulation increments means:
[a(t + s) - a(0)] = [a(t) - a(0)] + [a(s) - a(0)]
or
a(t + s) = a(t) + a(s) - 1 since a(0) = 1
In this case,
a(t + s) - a(t)
a (t) = lims0
s
a(t) + a(s) - 1 - a(t)
= lims0
s
a(s) - a(0)
= lims0
s
= a (0)
Thus the derivative is the same for all t, i.e. a(t) is a straight line and
a(t) = 1 + a (0)t = 1 + it for all t 0.
1-8
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