Physics Review Chapters 5-6, 8 - Allen Independent School ...



Unit 6 Physics Review Name _________________________

1) Energy is the ability to ____ .

A) produce no change

C) do work

B) burn something

D) none of the above

2) When a force is exerted on an object, no work is done if the object ____ .

A) is heavy

C) moves parallel to the force

B) is not heavy

D) moves perpendicular to the force

3) How much work is done if you raise a 5.0 N weight 3 m above the ground?

A) 0.0 J B) 2.5 J C) 7.0 J D) 15.0 J

4) What is the potential energy of a 5.0 N weight 3 m above the ground?

A) 0.0 J B) 2.5 J C) 7.0 J D) 15.0 J

5) One definition of power is ____ .

A) force exerted per unit

B) work done per unit of time

C) amount of energy expended distance

D) force applied multiplied by time

6) An object that has energy due to its shape or position possesses____.

A) potential energy B) chemical energy C) kinetic energy D) momentum

7) Which of the following is needed to find the kinetic energy of an object?

A) its shape B) its size C) its velocity D) its chemical composition

8) As the height above the Earth increases, the potential energy of the object ____.

A) increases B) decreases C) remains the same D) cannot tell

9) The kinetic energy of a book weighing 20.0 N book perched on the edge of a table 0.5 m high is ____.

A) 10.0 J B) 0 J C) 40.0 J D) 20.0 J

10) The potential energy of a book weighing 20.0 N book perched on the edge of a table 0.5 m high is ____.

A) 10.0 J B) 0 J C) 40.0 J D) 20.0 J

11) The amount of work done against gravity by lifting a 20.0 N book from the ground to the edge of a table 0.5 m high is ____.

A) 10.0 J B) 0 J C) 40.0 J D) 20.0 J

12) A change in the kinetic energy of an object is equal to the ____ .

A) net work done on the object

C) change in mass times velocity

B) work minus potential energy

D) 0.5 (W + PE)

13) Find the kinetic energy of the crate (below) that has a weight of 50 N.

14) Which of the following are forms of mechanical energy?

I) Elastic potential energy

II) Gravitational potential energy

III) Kinetic energy

IV) Thermal energy

A) II, III and IV B) I, II, and III C) I, II, IV D) I, II, III and IV

15) What is happening when some kinetic energy is converted to thermal energy?

A) Mechanical energy is being conserved.

B) Mechanical energy is not being conserved.

C) Mechanical energy is being converted to non-mechanical energy.

D) Both B and C

16) Suppose for a second that a VW beetle and Ford F150 have the same kinetic energy. The vehicle with more

speed is:

A) VW beetle (less mass) B) Ford F150 C) Both are the same speed

17) Which of the following would have the same units?

A) force : energy B) power : work C) force : power D) work : energy

18) A 30 kg student at rest is sitting on top of a frictionless slide that is 4.0 m high. At the top of the slide, the student has

A) all potential energy, no kinetic energy

B) mostly potential energy, some kinetic energy

C) mostly kinetic energy, some potential energy

D) all kinetic energy, no potential energy

19) A 30 kg student at rest is sitting on top of a frictionless slide that is 4.0 m high. When the student reaches the bottom of the slide, what has happened to the energy?

A) Some energy was loss due to friction.

B) All the kinetic energy was converted to potential energy

C) All the potential energy was convert to kinetic energy

D) All the potential energy was converted to mechanical energy

20) A 30 kg student at rest is sitting on top of a frictionless slide that is 4.0 m high. When the student reaches a height of 1.0 m, what is the kinetic energy of the child?

|Diagram: (Given + Unknowns) |Equation: ME = PE + KE ME = PE + KE |

| | |

|m = 30 kg h = 4.0 m g = 9.8 m.s2 | |

| | |

|m = 30 kg h = 1.0 m g = 9.8 m.s2 | |

| | |

|KE at 1 m in ???? J | |

| | |

|Top: PEi = mgh KEi = 0 J | |

| | |

|Middle: PE = mgh KE = 1/2mv2 | |

| | |

|Bottom PEf = 0 J KEf = 1/2mv2 | |

| |Substitute: at 4 m ME = PE + KE |

| |ME = mgh + 0 J |

| |ME = (30kg)(9.8 m/s2)(4 m) |

| |ME = 1176 J |

| |Mechanical Energy is conserved since no thermal energy is produced. |

| | |

| |at 1 m ME = PE + KE |

| |ME = mgh + KE |

| |1176 J = (30kg)(9.8 m/s2)(1 m) + KE |

| |1176 J = 294 J + KE |

| |882 J = KE |

Conservation of Energy Table for Question 20 (Notice Mechanical energy is conserved.)

|Height |Potential Energy |Kinetic Energy |Mechanical Energy |

|4 m |1176 J |0 J |1176 J |

|1 m |294 J |882J |1176 J |

|0 m |0 J |1176 J |1176 |

21) How much work is done by a 75 W light bulb that is left on for 90 seconds?

A) 6750.0 J B) .833 J C) 8.16 J D) 80.0 J

P = Work 75 = Work Work = 6750 J

t 90

|22) Use the following diagram for the following next six questions. You throw a 0.50 kg |[pic] |

|basketball off the Eiffel Tower in Paris, France. Lab | |

|I) Where does the ball have the most kinetic energy? ____D___ | |

|II) Where does the ball have the least kinetic energy? ___B___ | |

|III) Where does the ball have the most potential energy? __B__ | |

|IV) Where does the ball have the least potential energy? __D__ | |

|V) Where does the ball have no vertical speed ? _____B___ | |

|VI) Where is the ball moving the fastest? _____D_____ | |

23) How much energy does your 1600 W blow drier transfer if you dry your hair in 300 sec?

|Diagram: (Given + Unknowns) |Equation: P = W/t or E = Pt |

| | |

|P = 1600 W | |

|t = 300 s | |

|W = ???? J | |

| |Substitute: (1600 ) = Work |

| |(300 ) |

| | |

| |Work = (1600 ) (300 ) = 480,000 J |

| | |Solve: Work = 480,000 J |

24) How much power is developed by an electric motor that moves a 80 kg load through a distance of 20 m in 10 s?

|Diagram: (Given + Unknowns) |Equation: F = ma then W = fd then P = W/t |

|m = 80 kg | |

|d = 20 m | |

|t = 10 s | |

|P = ??? W | |

| |Substitute: |

| |F = ma = (80 )(9.8) = 784 N |

| | |

| |Work = fd = (784)(20 ) = 15,680 J |

| | |

| |P = Work / t = (15,680 ) / (10 ) = 1,568 W |

| | |Solve: P = 1,568 W |

25) It takes 800 J to lift a box 4 m in the air in 8 seconds. What is the weight of the box?

|Diagram: (Given + Unknowns) |Equation: W = Fd |

| | |

|W = 800 J | |

|d = 4 m | |

|t = 8 s | |

| | |

| | |

|Fg = ??? N | |

| | |

|Time isn’t needed | |

| |Substitute: 800 = F (4 ) |

| | |

| |F = 200 N |

| | |Solve: F = 200 N |

26) A spring is stretched 0.75 m. How much elastic potential energy is stored in the spring?

(spring constant of 12 N /m)

|Diagram: (Given + Unknowns) |Equation: PEelastic = (1/2)kx2 |

| | |

|d = x = 0.75 m | |

|spring constant = k = 12 N/m | |

| | |

|PEelastic = ????? J | |

| | |

| |Substitute: PEelastic = (1/2)(12 N/m)(0.75 m)2 |

| | |

| |PEelastic = 3.375 J |

| | |Solve: PEelastic = 3.375 J |

32) It takes 500 J of work to lift a puggle 1.7 meters off the floor. What is the magnitude of the force needed to lift the puggle?

|Diagram: (Given + Unknowns) |Equation: W = F(d) |

| | |

|W = 500 J | |

|d = 1.7 m | |

| | |

|F = ???? N | |

| |Substitute: (500 J) = F(1.7 m) |

| | |Solve: F = 294 N |

28) A puggle is sitting hanging out in her penthouse suite in that most lavish doggie hotel in Allen, TX. She is looking outside the window when she accidently drops her favorite doggie toy (a.200 kg stuffed mallard). It takes 3.19 seconds for the mallard to hit the ground. What is the final kinetic energy of the mallard before just before it hits the ground.

|Diagram: (Given + Unknowns) |Equation: a = (vf – vi ) / t then KE = 1/2mv2 |

| | |

|KEf = ??? J | |

|m = .200 kg | |

|vf = ??? m/s | |

|Vertical | |

|a = -9.8 m/s2 | |

|vf = ??? m/s | |

|vi = 0 m/s | |

|t = 3.19 s | |

|h = Δd = ??? m | |

| |Substitute: |

| |-9.8 = vf – 0 multiply -9.8 and 3.19 |

| |3.19 |

| | |

| |-31.2 m/s = vf (remember the negative only tells me direction.) |

| | |

| |KEf = (1/2)mv2 |

| |KE = (1/2)(.200)31.22 = 97. 7 J |

| | |

| |You could have also found the height first and then did PE = mgh |

| |Then PEi + KEi = PEf + KEf (where KEi and PEf equals zero.) |

| | |Solve: KE = 97.7 J |

29) Name one form of non-mechanical energy. Heat / thermal energy

30) A soccer player having less mass than a runner also accelerates uniformly from rest to a speed of 8 m/s. Compare the kinetic energies of the less massive soccer player to the kinetic energy of more massive runner when they are both traveling the same speed?

The soccer player with lass mass would have a lower kinetic energy.

The runner with more mass would have a higher a kinetic energy.

-----------------------

F = ma (50 N) = m (9.8 m/s2)

m = 5.1 kg

KE = (1/2)mv2 = (1/2)(5.1 kg)(6m/s)2 KE = 91.8 J

F = ma (50 N) = m (9.8 m/s2)

m = 5.1 kg

KE = (1/2)mv2 = (1/2)(5.1 kg)(6m/s)2 KE = 91.8 J

6.0 m/s

50 N

d = 20 m

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* |hîHðh4h?5?B*OJQJ^J[?]phÿ'

* |hîHðhiZ5?B* 80 kg

a = 9.8 m/s2

F = ?? N

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