Some continuous distributions - University of Connecticut
CHAPTER 10
Some continuous distributions
10.1. Examples of continuous random variables
We look at some other continuous random variables besides normals. Uniform distribution A continuous random variable has uniform distribution if its density is f (x) = 1/(b-a) if a x b and 0 otherwise.
For a random variable X with uniform distribution its expectation is
EX
=
b
1 -
a
^b
a
x dx
=
a
+ 2
b.
Exponential distribution A continuous random variable has exponential distribution with parameter > 0 if its density is f (x) = e-x if x 0 and 0 otherwise.
Suppose X is a random variable with an exponential distribution with parameter . Then we have
(10.1.1)
^
P(X > a) =
e-xdx = e-a,
a
FX (a) = 1 - P(X > a) = 1 - e-a,
and we can use integration by parts to see that EX = 1/, Var X = 1/2. Examples where an exponential random variable is a good model is the length of a telephone call, the length of time before someone arrives at a bank, the length of time before a light bulb burns out. Exponentials are memoryless, that is,
P(X > s + t | X > t) = P(X > s),
or given that the light bulb has burned 5 hours, the probability it will burn 2 more hours is the same as the probability a new light bulb will burn 2 hours. Here is how we can prove this
129
130
10. SOME CONTINUOUS DISTRIBUTIONS
P(X
>
s
+
t
|
X
>
t)
=
P(X > s + t) P(X > t)
=
e-(s+t) e-t
= e-s
= P(X > s),
where we used Equation (10.1.1) for a = t and a = s + t.
Gamma distribution
A continuous random variable has a Gamma distribution with parameters and if
its density is
f (x)
=
e-x(x)-1 ()
if x denote
0 and 0 otherwise. Here () such a distribution by (, ).
=
?
0
e-y
y-1
dy
is
the
gamma
function.
We
Note that see that
(1)
=
?
0
e-y dy
=
1,
and
using
induction
on
n
and
integration
by
parts
one
can
(n) = (n - 1)! so we say that gamma function interpolates the factorial.
While an exponential random variable is used to model the time for something to occur,
a gamma random variable is the time for events to occur. A gamma random variable,
n
d12e,gn2ree, swoitfhfrpeaedraomme.teRrsec12alalntdhan2t
is known as a 2n, a chi-squared random variable in Exercise 8.9 we had a different description of
with a 2
random variable, namely, Z2 with Z N (0, 1). Gamma and 2 random variables come up
frequently in statistics.
Beta distribution
A continuous random variable has a Beta distribution if its density is
f (x)
=
1 B(a,
b)
xa-1
(1
-
x)b-1,
where
B(a,
b)
=
?1
0
xa-1(1
-
x)b-1.
0 < x < 1,
This is also a distribution that appears often in statistics. Cauchy distribution
A continuous random variable has a Cauchy distribution if its density is
f (x)
=
1
1
1 + (x -
)2 .
10.1. EXAMPLES OF CONTINUOUS RANDOM VARIABLES
131
What is interesting about the Cauchy random variable is that it does not have a finite mean, that is, E|X| = .
Densities of functions of continuous random variables
Often it is important to be able to compute the density of Y = g (X), where X is a continuous random variable. This is explained later in Theorem 11.1.
Let us give a couple of examples. Example 10.1 (Log of a uniform random variable). If X is uniform on the interval [0, 1] and Y = - log X, so Y > 0. If x > 0, then
FY (x) = P(Y x) = P(- log X x) = P(log X -x) = P(X e-x) = 1 - P(X e-x) = 1 - FX (e-x).
Taking the derivative we see that
fY
(x)
=
d dx
FY
(x)
=
-fX (e-x)(-e-x),
using the chain rule. Since fX (x) = 1, x [0, 1], this gives fY (x) = e-x, or Y is exponential with parameter 1.
Example 10.2 (2, revisited). As in Exercise 8.9 we consider Y = Z2, where Z N (0, 1).
Then
FY (x) = P(Y = P(Z
x) = P(Z2
x) = P(-x
Z
x)
x)
-
P(Z
- x) = FZ( x) - FZ(- x).
Taking the derivative and using the chain rule we see
fY
(x)
=
d dx
FY
(x)
=
fZ( x)
21 x
- fZ(- x)
-21 x
.
Recall
that
fZ
(y)
=
1 2
e-y2/2
and
doing
some
algebra,
we
end
up
with
fY (x)
=
1 x-1/2e-x/2, 2
which is with one
deg12r,e12e
. As we pointed of freedom.
out
before,
this
is
also
a
2
distributed
random
variable
Example 10.3 (Tangent of a uniform random variable). Suppose X is a uniform random variable on [-/2, /2] and Y = tan X. Then
FY (x) = P(X tan-1 x) = FX (tan-1 x),
132
10. SOME CONTINUOUS DISTRIBUTIONS
and taking the derivative yields
fY (x)
=
fX
(tan-1
x)
1
1 +
x2
=
1
1
1 +
x2
,
which is a Cauchy distribution.
10.2. FURTHER EXAMPLES AND APPLICATIONS
133
10.2. Further examples and applications
Example 10.4. Suppose that the length of a phone call in minutes is an exponential random variable with average length 10 minutes.
(1) What is the probability of your phone call being more than 10 minutes?
Solution :
Here
=
1 10
,
thus
P(X
>
10)
=
e-(
1 10
)10
=
e-1
0.368.
(2) Between 10 and 20 minutes? Solution: We have that
P(10 < X < 20) = F (20) - F (10) = e-1 - e-2 0.233.
Example 10.5. Suppose the life of an Uphone has exponential distribution with mean life of 4 years. Let X denote the life of an Uphone (or time until it dies). Given that the Uphone has lasted 3 years, what is the probability that it will 5 more years.
Solution :
in
this
case
=
1 4
.
P (X
>
5
+
3
|
X
>
3)
=
P P
(X (X
> >
8) 3)
e-
1 4
?8
=
e-
1 4
?3
=
e-
1 4
?5
=
P (X
>
5) .
Recall that an exponential random variable is memoryless, so our answer is consistent with
this property of X.
? Copyright 2017 Phanuel Mariano, Patricia Alonso Ruiz, Copyright 2020 Masha Gordina.
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