Transformari identice ale expresiilor algebrice
sinxcos + cosxsin = 1, sin = 4/5; cos = 3/5, sin(x + ) = 1, tg = 4/3, c) Cum valoarea maxima a membrului din stanga ecuatiei este si rezulta ca ecuatia nu are solutii. Ecuatii de tipul F(sinx cosx, sinxcosx) = 0. Ecuatiile de asa tip se rezolva cu ajutorul substitutiei . Exemplul 16. Sa se rezolve ecuatiile: ................
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