CAT6 ISM, Chap 11

We now find u and v so that the first two terms of are 1 and 1 (Fibonacci sequence). Letting n = 1 and n = 2 yields u + v = 1 E1 u2 + v2 = 1 E2 Solving (steps omitted) gives u = v = − Therefore, an nth term formula for the Fibonacci sequence is given by (F) Outline of solution: The geometric sequence {rn} that satisfies cn = 6cn−1 – 3cn ... ................
................