MTH 133 Solutions to Exam 2 April 11th, 2018
MTH 133
Solutions to Exam 2
April 11th, 2018
Name:
Section:
Recitation Instructor:
INSTRUCTIONS ? Fill in your name, etc. on this first page.
? Without fully opening the exam, check that you have pages 1 through 12.
? Show all your work on the standard response questions. Write your answers clearly! Include enough steps for the grader to be able to follow your work. Don't skip limits or equal signs, etc. Include words to clarify your reasoning.
? Do first all of the problems you know how to do immediately. Do not spend too much time on any particular problem. Return to difficult problems later.
? If you have any questions please raise your hand.
? You will be given exactly 90 minutes for this exam.
? Remove and utilize the formula sheet provided to you at the end of this exam.
ACADEMIC HONESTY ? Do not open the exam booklet until you are instructed to do so.
? Do not seek or obtain any kind of help from anyone to answer questions on this exam. If you have questions, consult only the proctor(s).
? Books, notes, calculators, phones, or any other electronic devices are not allowed on the exam. Students should store them in their backpacks.
? No scratch paper is permitted. If you need more room use the back of a page. You must indicate if you desire work on the back of a page to be graded.
? Anyone who violates these instructions will have committed an act of academic dishonesty. Penalties for academic dishonesty can be very severe. All cases of academic dishonesty will be reported immediately to the Dean of Undergraduate Studies and added to the student's academic record.
I have read and understand the above instructions and statements regarding academic honesty: .
SIGNATURE
Page 1 of 12
MTH 133
Solutions to Exam 2
April 11th, 2018
Standard Response Questions. Show all work to receive credit. Please BOX your final answer.
1. Determine if the following series converge or diverge. If the series converges, also compute the sum. You must show all of your work and support your conclusions.
3n+1
(a) (7 points)
4n
n=0
Solution:
This series looks like a geometric series with r = 3/4 < 1, so it should converge. We can compute
its value as follows:
3n+1
4n = 3
n=0
n=0
3n
3
4
=
1
-
3 4
=
12 .
n2
(b) (7 points)
5n2 + 4
n=1
Solution:
Consider the nth-term test:
We compute the limit of the terms
n2
11
lim
n
5n2
+
4
=
lim
n
5
+
4 n2
=
5
= 0.
Because the limit of the terms is nonzero the series diverges.
Page 2 of 12
MTH 133
Solutions to Exam 2
April 11th, 2018
2. Determine if the following series converge or diverge. You must show all of your work and justify your use of any series convergence tests.
n5
(a) (7 points)
5n
n=1
Solution:
Use the ratio test:
lim
n
an+1 an
=
lim
n
(n + 1)5 5n+1
?
5n n5
=
lim
n
(n
+ 1)5 n5
?
1 5
= lim n + 1 5 ? 1
n n
5
= lim
1 1+
5?1
n
n5
1 = < 1.
5
Thus, the series converges.
1
(b) (7 points)
2n - 1
n=1
Solution:
Consider the ratio test:
lim
n
an+1 an
=
lim
n
1 2n+1 - 1
? 2n
-1
2n - 1
=
lim
n
2n+1
-
1
=
lim
n
1 2
- -
1 2n 1 2n
1 = ................
................
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