Jacobi Method: Eigenvalues and Eigenvectors
from numpy import array,identity,diagonal from math import sqrt def Jacobi(A,tol = 1.0e-9): # Jacobi method # Find largest off-diagonal element a[k,l] def maxElem(A): n = len(A) Amax = 0.0 for i in range(n-1): for j in range(i+1,n): if abs(A[i,j]) >= Amax: Amax = abs(A[i,j]) k = i; l = j return Amax,k,l ................
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