How do you write the equation of a line



How do you write the equation of a line?

Given Example Your Turn

|*****Slope and Y-intercept***** |***Slope = ¾, y-intercept = -2*** |***Slope = - ½ , y-intercept = 5*** |

|Use the slope-intercept form of the equation: | | |

|y = mx + b | | |

|Substitute for m and b. | | |

|*****Slope and a Point***** |***Slope = -3, Point = (-2, 4)*** |***Slope = 4, Point = (-6, -4)*** |

|Use the point-slope form of the equation: | | |

|y – y1 = m(x – x1) | | |

|Substitute for m, x1 and y1. Solve for y. | | |

| | | |

|*****Two Points***** |*** Points are (-6, 3) and (2, -7)*** |*** Points are (-9, -2) and (1, -8)*** |

|Use the slope formula and the coordinates of the two points to find the slope. | | |

|M = rise = y2 – y1 | | |

|run x2 - x1 | | |

|Use this slope and one of the given points to write the equation of the line | | |

|following the ****Slope and a Point***** method above. | | |

|***Point and the Equation of a Parallel Line*** |*** Point is (-6, -3) and parallel line’s equation is 3x + 4y |*** Point is (-2, 5) and parallel line’s equation is 3x - 6y |

|Solve the equation of the parallel line for y and find its slope. |= 6*** |= 4*** |

|Use this slope and the given point to write the equation of the line following the | | |

|*****Slope and a Point***** method above. | | |

|**Point and the Equation of a Perpendicular Line** |*** Point is (6, -4) and perpendicular line’s equation is 3x -|*** Point is (6, -4) and perpendicular line’s equation is 3x |

|Solve the equation of the perpendicular line for y and find its slope. |2y = -6*** |+ 4y = -8*** |

|Use the opposite reciprocal of that slope and the given point to write the equation | | |

|of the line following the *****Slope and a Point***** method above. | | |

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Graphic Organizer by Dale Graham and Linda Meyer

Thomas County Central High School; Thomasville GA

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