CHAPTER 2 Giancoli: Physics

We find the time of flight from the horizontal motion: x = v0xt; 120 m = (250 m/s)t, which gives t = 0.480 s. We find the distance the bullet falls from. y = - ½ g t2; y = - ½ (9.80 m/s2)(0.480 s)2 = - 1.13 m. (b) The bullet will hit the target at the same elevation, so we can use the expression for the . horizontal range: ................
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