CAT6 ISM, Chap 11
We now find u and v so that the first two terms of {u4n + v(−1)n} are 5 and 55. Letting n = 1 and n = 2 yields 4u – v = 5 16u + v = 55 Solving yields u = 3, v = 7. Therefore, an nth term formula for the original sequence is bn = 3 · 4n + 7(−1)n. ................
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