07 - Area Between Curves
[Pages:4]Kuta Software - Infinite Calculus
Area Between Curves
Name___________________________________ Date________________ Period____
For each problem, find the area of the region enclosed by the curves.
1) y = 2x2 - 8x + 10 x2
y = - 2x - 1 2
x = 1 x = 3
y 8
2) x = 2 y2 + 12 y + 19 y2
x = - - 4 y - 10 2
y = -3 y = -2
y 8
6
6
4
4
2
2
-8 -6 -4 -2 -2 -4 -6 -8
2 4 6 8x
-8 -6 -4 -2 -2 -4 -6 -8
2 4 6 8x
x2
1
3) y = - 3x -
2
2
y = 3
y 8
6
4
2
-8 -6 -4 -2 -2 -4 -6 -8
2 4 6 8x
4)
x3 y = -
+ 2x2
2
y = -x2 + 4x
y 8
6
4
2
-8 -6 -4 -2 -2 -4 -6 -8
2 4 6 8x
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-1-
Worksheet by Kuta Software LLC
For each problem, find the area of the region enclosed by the curves. You may use the provided graph to sketch the curves and shade the enclosed region.
5) y = -2x2 - 1 y = -x + 3 x = 0 x = 1
y 8
6
4
2
-8 -6 -4 -2 -2 -4 -6
2 4 6 8x
6) y = 2 3 x2 y = x
y 8
6
4
2
-8 -6 -4 -2 -2 -4 -6 -8
2 4 6 8x
-8
7) y = -x3 + 6x y = -x2
y 8
6
4
2
-8 -6 -4 -2 -2 -4 -6 -8
2 4 6 8x
8) y = -2 sec2 x y = 2cos x x = 0 x = 4
y 4
3
2
1
-
-
2 -1
2
-2
-3
-4
x
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-2-
Worksheet by Kuta Software LLC
Kuta Software - Infinite Calculus
Area Between Curves
Name___________________________________ Date________________ Period____
For each problem, find the area of the region enclosed by the curves.
1) y = 2x2 - 8x + 10 x2
y = - 2x - 1 2
x = 1 x = 3
y 8
2) x = 2 y2 + 12 y + 19 y2
x = - - 4 y - 10 2
y = -3 y = -2
y 8
6
6
4
4
2
2
-8 -6 -4 -2 -2 -4 -6 -8
2 4 6 8x
( ( )) 3 2x2 - 8x + 10 -
x2
- 2x - 1
dx
2
1
= 11
-8 -6 -4 -2 -2
2 4 6 8x
-4
-6
-8
( ( )) -2 2 y2 + 12 y + 19 -
y2 -
- 4 y - 10
dy
2
-3
29 = 4.833
6
x2
1
3) y = - 3x -
2
2
y = 3
y 8
6
4
2
4)
x3 y = -
+ 2x2
2
y = -x2 + 4x
y 8
6
4
2
-8 -6 -4 -2 -2
2 4 6 8x
-4
-6
-8
( ( )) 7
x2
1
3 - - 3x - dx
2
2
-1
128 = 42.667
3
-8 -6 -4 -2 -2
2 4 6 8x
-4
-6
-8
( ( )) 2 -x2 + 4x -
x3 -
+ 2x2
dx +
2
0
( ) 4 x3 -
+ 2x2 - (-x2 + 4x)
dx
2
2
= 4
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-1-
Worksheet by Kuta Software LLC
For each problem, find the area of the region enclosed by the curves. You may use the provided graph to sketch the curves and shade the enclosed region.
5) y = -2x2 - 1 y = -x + 3 x = 0 x = 1
y 8
6
4
2
-8 -6 -4 -2 -2 -4 -6 -8
2 4 6 8x
1 (-x + 3 - (-2x2 - 1)) dx
0
25 = 4.167
6
6) y = 2 3 x2 y = x
y 8
6
4
2
-8 -6 -4 -2 -2 -4 -6 -8
2 4 6 8x
8 (2 3 x2 - x) dx
0
32 = = 6.4
5
7) y = -x3 + 6x y = -x2
y 8
6
4
2
-8 -6 -4 -2 -2
2 4 6 8x
-4
-6
-8
0 (-x2 - (-x3 + 6x)) dx +
-2
3 (-x3 + 6x + x2) dx
0
253 = 21.083
12
8) y = -2 sec2 x y = 2cos x x = 0 x = 4
y 4
3
2
1
-
-
2 -1
x
2
-2
-3
-4
4 (2cos x + 2 sec2 x) dx
0
= 2 + 2 3.414
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Worksheet by Kuta Software LLC
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