Summary and examples for section 14

We first compute the first partial derivatives: f x = 4x-2y and f y = -3y2-2x. Since both derivatives are defined for all (x, y), the critical points are solutions of the two equations: f x = 4x-2y = 0 and f y = -3y2-2x = 0. Solving the first equation for y, we get y = 2x. Substituting this into the second equation, we have ................
................