Honors Chemistry I

27.91 g Fe x (1 mol / 55.845 g) = .49978 / .49978 = 1 x 2 = 2. 24.08 g S x (1 mol / 32.065 g) = .75097 / .49978 = 1.503 x 2 = 3. 48.01 g O x (1 mol / 15.999 g) = 3.0008 / .49978 = 6.019 x 2 = 12 Fe2S3O12 → Fe2(SO4)3 – iron(III) sulfate or ferric sulfate 3. A certain compound is known to have a molecular weight slightly under 320 grams. ................
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