FOUR PRACTICE PROBLEMS--PERMUTATIONS AND …

4. Card Game. a. Method One: There are C(52,5) = 2,598,960 possible hands. 48 of these contain 4 aces (4 aces and the king of spades, 4 aces and the queen of spades, 4 aces and the jack of spades, etc.). 48 / 2,598,960 = 0.000018469, or one chance in 54,145. Or, the "sequential approach." ................
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