Charles’ Law Worksheet ANSWER KEY
Pressure Units ANSWER KEY
1) 73kPa
2) 3.21atm
3) 48.0torr
4) 2800mmHg
5) 304.5kPa
6) 1410mmHg
Kelvin Temp ANSWER KEY
1) 299.0K
2) -173K
3) 146K
4) 127oC
5) 408K
6) -269oC
7) 706K or 433oC
Charles’ Law Worksheet ANSWER KEY
1) 0.47 L
2) 0.71 L
3) 285 mL
4) 1.81 L
5) 2.35 L
6) 51,800 K
7) The temperature is 298.5 K = 0.50 C. A jacket would be appropriate clothing for this weather.
Boyles’ Law – ANSWER KEY
1) 2.11 atm
2) 2.0 x 105 L
3) 3.33 x 10-5 L
4) 72.7 L
5) 2.0 x 103 L
6) 600 L
7) 72 L
8) V = 0.25 L, yes
Avogadro’s Law - Answer Key
1) 21.6 L
2) 16.8 L
3) 435 L
4) 2.59g
Dalton’s Law – Answer Key
1) 9.00 atm
2) 1.20 atm He, 2.80 atm Ar
3) A. 15.00 mol B. 19.98 mol C. 34.98 mol D. don’t do
E. 0.5712 XHe F. 3.00 atm G. 4.00 atm
Gay-Lussac’s Law – Answer key
1) P2 = 1.03 atm. Therefore the ΔP = 0.03 atm.
2) 0.313 atm
3) 340.3 K (67.3 oC)
4) 634.2 mm Hg
5) 317.9 K (44.9 oC)
6) 3.31 atm
7) 1.06 x103 mm Hg
8) 173 kPa
9) 30.4 atm
Graham’s Law – Answer Key
1) He effuses 3.16x faster
2) 5000 g/mol
3) 14.2 hrs
4) 3.2 g/L
5) 5.64 x
Combined Gas Law Problems - Solutions
1) 29.6 L
2) 30.5 L
3) 2.51 atm
4) 4.74 L
5) 136 atm
6) 117 L
7) 30.3 L
8) 160 K
9) 7.41 L
Ideal Gas Law Problems – Answer Key
1) 205 K
2) 1.26 moles
3) 1.64 atm
4) 2310 L
5) 5.34 atm
6) 0.51 moles
7) 19.9 L
8) 1603 K
9) 1.62 atm
10) 143 moles
11) 0.97 L
12) 13.3 moles
Miscellaneous Problems – Answer Key
1) 313.15 K
2) 253.15 K
3) 293.15
4) -21.15 oC
5) 128.15 K
6) 24.85 oC
7) 1.053 atm, 106.7 kPa
8) 30002 mm Hg
9) 12844 mm Hg
10) 36345 Pa
11) 1.079 atm
12) 91900 Pa
13) 2840 kPa
14) 237 K
15) 1470 mm Hg
16)
A. Assuming the container is inflexible, the pressure inside the container would increase. The average kinetic energy of the particle increases, which increases the speed of the particles. The increased speed causes a greater number of collisions (with higher energy) on the inside surface of the container.
B. The particles will have a lower kinetic energy, and the volume of the gas will decrease.
C. By adding more particles, the average kinetic energy would increase due to an increased number of collisions. Since temp. is directly related to average kinetic energy, the gas would have to be cooled to keep P & V constant.
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