Unit 9 Worksheet 7



Algebra 2 Name ___________________________

Unit 11.10 Period 1 2 3 4 5 6 7

Factor and Solve a Trinomial Quadratic with a

Leading Coefficient > 1

NOTES:

Recall… Multiply the binomials. [pic] These are the factors of the     trinomial answer your will get after                        FOILing the binomials.

Steps to Factoring and Solving a Trinomial when the Leading Coefficient is > 1

[pic]

Ex: [pic]

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EXAMPLES:

FACTOR SOLVE

1. [pic]= 0

FACTOR SOLVE

2. [pic] = 0

3. [pic]= 0

4. [pic]= 0

5. [pic]

6. 50x2 - 2 = 0

Algebra 2 Name_______________________

11.10  Factoring and Solving a Quadratic Period 1 2 3 4 5 6 7

 Equation with a Leading Coefficient > 1

  

ASSIGNMENT

|Factor and solve the quadratic equation.                C and B Level |

| FACTOR SOLVE |

|1. [pic]= 0 |

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| FACTOR SOLVE |

|2. [pic]= 0 |

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| FACTOR SOLVE |

|3. [pic]= 0 |

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| FACTOR SOLVE |

|4. [pic]= 0 |

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| FACTOR SOLVE |

|5. [pic]= 0 |

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| FACTOR SOLVE |

|6. [pic]= 0 |

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| FACTOR SOLVE |

|7. [pic]= 0 |

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| FACTOR SOLVE |

|8. [pic]= 0 |

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|Factor out the GCF, factor the remaining trinomial, and then solve the quadratic equation.                          A Level |

| FACTOR SOLVE |

|9. [pic]= 0 |

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| FACTOR SOLVE |

|10. [pic]= 0 |

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| FACTOR SOLVE |

|11. [pic]= 0 |

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| FACTOR SOLVE |

|12. [pic]= 0 |

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| FACTOR SOLVE |

|13. [pic]= 0 |

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| FACTOR SOLVE |

|14. [pic]= 0 |

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| FACTOR SOLVE |

|15. [pic]= 0 |

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11.10 Practice Test

|1C. Factor. |1B. Solve by factoring. |1A. Solve by factoring. |

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RANDOM ANSWERS

|(x+1)(3x+4)=0 | (2x-3)(3x+4)=0 | (x-1)(5x-12)=0 |

|x = -1, -4/3 |x = 3/2, -4/3 |x = 1, 12/5 |

|(x+1)(2x+3)=0 | (x+7)(2x+1)=0 | (x-1)(7x-2)=0 |

|x = -1, -3/2 |x = -7, -1/2 |x = 1, 2/7 |

| (7x-1)(7x+1)=0 |4(2x-1)(2x+1)=0 | (5x+3)(5x-3)=0 |

|x = -1/7, 1/7 |x = -1/2, ½ |x = -3/5, 3/5 |

|(x+6)(2x+1)=0 | (3x-2)(3x+2)=0 |1C (x-4)(2x+3) |

|x = -6, -1/2 |x = -2/3, 2/3 | |

|5(2x-3)(x+1)=0 |3(2x-3)(3x+4)=0 |1B (x+4)(5x+1)=0 |

|x = -1, 3/2 |x = 3/2, -4/3 |x = -4, -1/5 |

| (2x-9)(2x-1)=0 |4(2x-1)(3x+1)=0 |1A 2(x-3)(2x+7)=0 |

|x = 9/2, ½ |x = -1/3, ½ |x = 3, -7/2 |

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