PROVINCIAL ASSESSMENT GRADE 11

[Pages:9]PROVINCIAL ASSESSMENT

GRADE 11

MATHEMATICAL LITERACY P2 NOVEMBER 2019

MARKING GUIDELINES

MARKS: 100

SIMBOL M MA CA A C S RT SF O P R NPR AO J MCA

MEMORANDUM

EXPLANATION Method Method with accuracy Consistent accuracy Accuracy Conversion Simplification Reading from table/graph/map Correct substitution in formula Opinion/Explanation Penalizing, ea. for no units, incorrect rounding off, etc. Rounding off No penalty for rounding. Answer only Justification Method with consistent accuracy

These marking guidelines consist of 7 pages and 2 pages containing cognitive levels

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QUESTION 1 [27 marks]

Ques. Solution

1.1.1

%

=

250-200 200

? 100

=

50 200

?

100

= 25%

1.1.2 Carry goods OR Make art/Fishing lines

OR Paint OR Protect OR Packaging

Any valid advantage

1.1.3 1989 and 2002

1.1.4 Glass OR Paper Any relevant suggestion

Explanation 1 SF Substitution 1 M Difference

1 A Answer 2 O Opinion

1 A 1989 1 A 2002 2 O Opinion

Level 2

(3) 4

(2) 2

(2) (2) 4

1.2.1 1.2.2

Average

=

385

558 5

77 112 tons OR 77 112

49+52 = 50,5%

2

1 M Concept 1 M Adding all values 1 A Answer 1 M Concept of median 1 A Answer NPR

2

(3) 2

(2)

1.3.1 1.3.2

Surface Area = 4 ? 10 ? 6 + 2 ? 6 ? 6

= 240 + 72 = 312 cm2 Cardboard needed = 312 + 5 ? 312

100

= 327,6 cm2

OR

Surface Area = 4 ? 10 ? 6 + 2 ? 6 ? 6

= 240 + 72 = 312 cm2 Cardboard needed = 105 ? 312

100

= 327,6 cm2

OR

Surface Area = 2[6 ? 6 + 6 ? 10 + 6 ? 10]

= 72 + 240

= 312 cm2 Cardboard needed = 312 + 5 ? 312

100

= 327,6 cm2

OR

Surface Area = 2 ? (6 ? 6) + 24 ? 10

=312 cm2 Cardboard needed = 312 + 5 ? 312

100

= 327,6 cm2

327,6 ? 1,2c

= 393,12c

= R3,93

The claim is not valid

1 SF Substitution

1 A Answer

1 M % calculations 1 A Answer OR 1 SF Substitution

1 A Answer 1 M % calculations 1 A Answer OR 1 SF Substitution

1 A Answer

1 M % calculations 1 A Answer OR 1 SF Substitution 1 A Answer 1 M % calculations 1 A Answer

CA from Q1.3.1 1 M Multiplying by 1,2 1 CA Answer 1 C Convert to Rand 1 Opinion

3

(4) 4

(4)

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1.3.3

On

the

length

=

31 6

=

5,17

5

On

the

width

=

24 6

=

4

On

the

height

=

25 10

=

2,5

2

Number of containers = 5 ? 4 ? 2 = 40

Claim is valid

QUESTION 2 [24 marks]

Ques. Solution

2.1.1 2.1.2

2.1.3

NE

From Port Elizabeth take the N10 to Colesberg.Turn right on the N1 to Bloemfontein.

1 : 10 000 000 1 cm 100 km 5,5 cm 5,5 ? 100 = 550 km OR 5,5 ? 10 000 000 = 55 000 000 = 55 000 000

100 000

= 550 km (accept between 5,3 cm and 5,7 cm 530 to 570 km)

2.2.1

Time =

=

325 90 /

= 3,6 hour

His claim is not valid

OR

Distance covered in 4 hours

90

km/h

=

Distance 4 h

Distance = 90 ? 4

= 360 km

His claim is not valid

OR

Speed

=

= 81,25 km/h

His claim is not valid

2.2.2

6 ? 325

100

=19,50 litres

Cost = 19,50 ? 13,95

= R272,025

Return trip = R272,025 ? 2

= R544,05

The farmer's statement is not correct

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1 A length 1 A width

1 A height 1 A Number of boxes

1 O Opinion

4 (5)

Explanation

Level

2 A Answer

(2) 2

2 RT Reading from map

2

(2)

1 C Conversion

3

1 M Measurement

1 M Multiplying by 100

1 A Answer

OR

1 M Measurement

1 M Multiplying by 10 000 000

1 C Conversion

1 A Answer

(4)

4 1 Substitution

1 A Answer 1 O Opinion OR

1SF Substitution 1 A Answer 1 O Opinion OR 1SF Substitution 1 A Answer 1 O Opinion

1 A Consumption rate

(3) 4

1 CA Cost 1 M Multiplying by 2 1 CA Return trip cost 1 J Justification

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2.2.3 2.2.4

OR 6 ? 325

100

=19,50 litres Return trip = 19,5 ? 2

= 39 litres

Cost = 39 ? 13,95 = R544,05

The farmer's statement is not correct

Radius

=

1,75 2

= 0,875

V = 2

= 3,142 ? (0,875)2 ? 7

= 16,839... 3

= 16 839 litres

16

839

?

0,01 100

?

16

839

= 16 837,32 l

Number

of

2

l

containers

=

16

837,32 2

= 8 418

OR

99,99 100

?

16

839

=16 837,32 l

Number of 2 l

containers

=

16

837,32 2

= 8 418

OR

1 A Consumption rate

1 M Multiplying by 2 1 CA Return trip litres 1 CA Cost 1 J Justification NPR

1 M Radius

1 SF Substitution

1 A Answer 1 C Conversion

1 M % calculation 1 A Answer

1 M Dividing by 2 1 A Answer OR 1 M % calculation 1 A Answer

1 M Dividing by 2 1 A Answer

(5) 3

(4) 3

(4)

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QUESTION 3 [28 marks]

Ques. Solution

3.1.1(a) R0,00 3.1.1(b) R180 3.1.1(c) 150

Explanation

1 A R0,00 1 A R180 2 A 150

Level

2 2 (4) 2

3.1.2

Cost in rand

400

Call costs

380

360

340

KEUSE B

320

300

Option B

280

OPTION B

260 240

X

X

Option B KEUSE B

220

X

200

X ))

180

160

140

120

100

OPTION A

80

60

40

20

0

0

20

40

60

80

100 120 140 160 180 200

Call time in minutes

3.1.3 3.1.4 3.1.5

Naming of the graph

1 A

(0;180)

1 A

(80;180)

1 A

(120;240)

1 A

Break-even-point (X)

1 A

Joining points

1 A

Where both options costs the same amount for the 2 O Opinion

same talk time

When the talk time is less than 120 minutes

CA From Q3.1.2

2 O Opinion

2019 ? 1973

1 M Subtraction

= 46 years

1 A Answer

No

1 J Justification

(6) 3 4

(2) 4

(2) 4

(3)

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3.2.1

3.2.2 3.3.1 3.3.2

2 + 3 = 5

R108

=

3 5

?

Total

amount

Total

amount

=

R108

?

5 3

= R180

OR

Calls:Data = 2:3

x:R108

3x = R216

Calls = x = R72

Total amount = R180

Surf the web OR App download OR

Software update OR Watch videos OR

Send emails OR Check facebook OR

Twitter OR Whatsapp

15 32

OR 0,47 OR 46,88%

49 ? 32 = 17 learners

17 49

?

100

= 34,69%

1 M Adding

3

1 SF Substitution

1

M

Multiplying

by

5 3

1 A Answer

OR

1 Ratio 1 SF Substitution 1 M Calculating x 1 A Answer

2 O Opinion

(4) 4

(2)

2 A Answer

2 (2)

1 A Number of learners 3

1 M Multiplying fraction

by 100

1 A Answer

(3)

QUESTION 4 [21 marks] Ques. Solution

4.1.1 4.1.2

BM I

80 (1,67)

2

= 28,69 kg/m2

Overweight

Do exercises OR Loose weight Eat healthy food OR Consult a dietician Any logical answer.

4.2.1

Original price = R610 + R8 230 = R8 840

610 ? 100%

8840

= 6,9% Her claim is not valid

OR

Original price

= R610 + R8 230

= R8 840

7 100

?

8840

= R618,80

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Explanation

Level

1 SF Substitution 1 A Answer 1 A Answer

2 O Opinion

2

(3) 4

(2)

4

1 A Original price

1 M % Calculation 1 A Answer

1 O Opinion

OR

1 A Original price 1 M % Calculation 1 A Answer

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4.2.2

Her claim is not valid

1 0,07

?

610

=R8 714,29

Her statement is not correct.

1 O Opinion

(4)

1 M Dividing by 0,07

4

1 A Answer

1 J Justification

(3)

4.3.1

Inflation rate in Namibia from 2010 to 2017

2

9

8

7

6

5

Inflation rate

4

3

2

1

0 2010 2011 2012 2013 2014 2015 2016 2017

Year

4.3.2

4.3.3 4.3.4

47,2 8

=

5,9%

6,7% The inflation rate decreases from 2014 to 2015 The inflation rate increases from 2016 to 2017

1 A for 2014 1 A for 2015 1 A for 2016

1 MA dividing by 8 1 A Answer 2 A Answer 1 A Decreases 1 A Increases

(3) 2

(2) (2) 2

4 (2)

TOTAL: 100

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CONTENT COMPOSITION

TAXONOMY LEVELS

Qu. 1 1.1.1 1.1.2 1.1.3 1.1.4 1.2.1 1.2.2 1.3.1 1.3.2 1.3.3

Finances Measuring Maps Data Physical world

4 5

3 2 2 2 3 2 4

Proba bility

2 3 4 Total

3

3

2 2

2

2

2 2

3

3

2

2

4

4

4 4

5 5

27

Qu. 2

2.1.1

2.1.2

2.1.3

2.2.1

3

2.2.2

5

2.2.3

4

2.2.4

4

Qu. 3

3.1.1

4

3.1.2

6

3.1.3

2

3.1.4

2

3.1.5

3

3.2.1

4

3.2.2

2

3.3.1

3.3.2

Qu. 4

4.1.1

4.1.2

4.2.1

4

4.2.2

3

4.3.1

4.3.2

4.3.3

4.3.4

TOTAL 36

19

2 2 4

2 3

3 2

3 2 2 2

17

23

5

2

2

2

2

4

4

3 3

5 5

4

4

4

4

24

4

4

6

6

2 2

2 2

3 3

4

4

2 2

2

2

3

3

28

3

3

2 2

4 4

3 3

3

3

2

2

2

2

2 2

21

30 29 41 100

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