GRADE 10 JUNE 2011 MARKING MEMORANDUM



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PUNTE: 150

TYD: 3 uur

Hierdie memo bestaan uit 8 bladsye

GRAAD 10 JUNIE 2011 MEMORANDUM VAN PUNTE TOEKENNING

|AFDELING A | |

|VRAAG 1 | |

|1.1 |Verplasing | |

|1.2 |Skalaar | |

|1.3 |Versnelling | |

|1.4 |Gewig | |

|1.5 |Gravitasieveld 5x1 |[5] |

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|VRAAG 2 | |

|2.1 |B | |

|2.2 |D | |

|2.3 |E | |

|2.4 |C | |

|2.5 |F 5X1 |[5] |

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|VRAAG 3 | |

|3.1 |A | |

|3.2 |C | |

|3.3 |B | |

|3.4 |C | |

|3.5 |D 5x3 |[15] |

| |TOTAAL AFDELING A: |25 |

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|AFDELING B | |

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|VRAAG 4 | |

|4.1 |Verplasing vir die hele beweging gedeel deur die tyd wat dit neem vir die totale beweging OF |(2) |

| |Resulterende/netto verplasing gedeel deur die tyd geneem vir die totale beweging | |

|4.2 |O na A: beweeg noord met uniforme versnelling | |

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| |A na B: beweeg noord teen konstante snelheid | |

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| |B na C: beweeg noord teen konstante negatiewe versnelling | |

| | |(4) |

| |C na D: beweeg suid teen dieselfde versnelling soos tussen B na C | |

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|4.3.1 |O to/na A: ½ x2x20 = 20 m |(1) |

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|4.3.2 |A to/na B: 2x20 = 40 m |(1) |

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|4.3.3 |B to/na C: ½ x2x20 = 20 m |(1) |

|4.4 |20 + 40 + 20 + (1/2x1x(-5)) = 77,5 m north/noord |(3) |

|4.5 |Tussen 4 s en 6 s en tussen 6 s en 7 s |(2) |

|4.6 |3,6 x 20 = 72 km.h-1 |(2) |

|4.7.1 |aOA = [pic] = 10 m.s-2 noord | |

| | |(5) |

|4.7.2 |aBC = [pic] = -10 m.s-2 suid | |

| | |(4) |

|4.7.3 |aCD = [pic] = - 10 m.s-2 m.s.-2 suid | |

| | |(4) |

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|4.8.1 | | |

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| | |(5) |

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|4.8.2 | | |

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| | |(5) |

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|4.9 |vav = [pic] = 10,71 m.s-1 north |(5) |

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| | |[44] |

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|VRAAG 5 | |

|5.1 |Die som van (gravitasie) potensiële energie en kinetiese energie |(2) |

|5.2 |Die meganiese energie/som van potensiële energie en kinetiese energie van ‘n geïsoleerde/geslote sisteem |(2) |

| |bly behoue/ bly constant | |

|5.3.1 |Fg or /of w = m x g = 5 x 9,8 = 49 N na die aarde/na die aarde se middelpunt/vertikaal afwaarts |(4) |

|5.3.2 |UP = mg∆y = 5 x 9,8 x 100 = 4900 J |(4) |

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|5.4 |(U + K)P = (U + K)X | |

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| |(mg∆y)P + (1/2 mv2)P = (mg∆y)X + (1/2 mv2)X | |

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| |(mg∆y)P + 0 = 0 + (1/2 mv2)X | |

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| |5 x 9,8 x 100 + 0 = 0 + ½ x 5 x vX2 | |

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| |vX2 = [pic]= 1960 (vX = [pic]= 44,27 m.s.-1 | |

| | |(5) |

|5.5.1 |(U + K)P = (U + K)Y | |

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| |(mg∆y)P + (1/2 mv2)P = (mg∆y)Y + (1/2 mv2)Y | |

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| |(mg∆y)P + 0 = 0 + (1/2 mv2)X (vir 0) | |

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| |5 x 9,8 x 100 + 0 = 0 + ½ x 5 x vX2 | |

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| |vY2 = [pic]= 1960 (vY = [pic]= 44,27 m.s.-1 = vX | |

| | |(6) |

|5.5.2 |Meganiese energie by P word by beide X en Y behou |(3) |

| | |[26] |

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|VRAAG 6 | |

|6.1 |Termiese geleiers | |

| |Elektriese geleiers | |

| |Blink metaalglans | |

| |Pletbaar | |

| |Rekbaar | |

| |Reikwydte van smeltpunte | |

| |Enige 3: 3x1 |(3) |

|6.2.1 |Plastiek 6.2.6 Fe of Cu | |

|6.2.2 |H2O 6.2.7 B | |

|6.2.3 |Fe 6.2.8 Fe of Cu | |

|6.2.4 |Ge 6.2.9 Swawel of B | |

|6.2.5 |MgSO4 6.2.10 H2O(ℓ) |(10) |

| |10x1 |[10] |

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|VRAAG 7 | |

|7.1 |Die temperatuur waarteen die dampdruk van ‘n stof gelyk is aan atmosferiese druk | |

| | |(2) |

|7.2 |Fisiese verandering | |

| | |(2) |

| |Dit is ‘n tydelike verandering of Dit is omkeerbaar | |

|7.3.1.1 | Molekulêre grootte of kettinglengte |(1) |

|7.3.1.2 |Kookpunt |(1) |

|7.3.1.3 |Homoloë reeks of Klas van verbindings of Alkane |(1) |

|7.3.2.1 |Wat is die verwantskap tussen molekulêre grootte en kookpunt? | |

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| |Dit is ‘n verwantskap tussen die korrekte veranderlikes | |

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| | |(2) |

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| |Dit is ‘n vraag | |

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|7.3.2.2 |Kookpunt neem toe (of neem af) met toename (of afname) in molekulêre massa/kettinglengte | |

| |OF Kookpunt is direk eweredig aan molekulêre grootte of kettinglengte OF Kookpunt is omgekeerd eweredig aan | |

| |molekulêre grootte of kettinglengte | |

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| |Dit is ‘n verwantskap tussen die korrekte veranderlikes | |

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| |Dit is ’n stelling | |

| | |(2) |

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|7.3.3 |CH4 OF metaan | |

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| |Dit het die kleinste grootte /kettinglengte en dus is die intermolekulêre kragte tussen CH4 molekules die | |

| |kleinste (of die minste energie is benodig om CH4 molekules te skei.) |(3) |

|7.3.4 |C4H10 | |

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| |C4 |(2) |

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| |H10 | |

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|7.3.5 |Kookpunt neem toe soos molekulêre grootte/ kettinglengte toeneem |(2) |

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| | |[18] |

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|VRAAG 8 | |

|8.1 |Atome van dieselfde element wat dieselfde aantal protone (of wat dieselfde atoomgetal het) maar | |

| |verskillende getalle neutrone (of verskillende massagetalle het) |(2) |

|8.2.1 |Tritium 8.2.3 1 |(2) |

|8.2.2 |3 8.2.4 1 |(2) |

|8.2.5 |3-1 = 2 |(2) |

|8.2.6 |3 |(1) |

|8.3.1 |[pic] | |

| |[pic]H | |

| | |(2) |

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| |[pic]H | |

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|8.3.2 |Beide het 1 proton | |

| |[pic] het 1 neutron meer as[pic] |(4) |

|8.4.1 |12 |(2) |

|8.4.2 |Relatiewe atoommassa / = [pic] = 24,3 |(5) |

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| | |[22] |

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|VRAAG 9 | |

|9.1 |K ( T en K = ½ mv2 | |

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| |As T verdubbel word, word K ook verdubbel, om 2K te gee | |

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| |2K = 2 (½ mv2) = ½ m([pic]v)2 | |

| | |(5) |

| |Dus neem die spoed van die molecules met die faktor [pic] toe | |

| | |[5] |

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| |TOTAAL AFDELING B: |125 |

| |GROOTTOTAAL: |150 |

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VOORBEELD EKSAMENVRAESTEL

GRAAD 10

MEMO

Asse

FISIESE WETENSKAPPE V1 en V2

FISIKA en CHEMIE

JUNIE 2011

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