Graphing Linear Equations
Graphing Linear Equations
To graph a line (linear equation), we first want to make sure the equation is in slope intercept form (y=mx+b). We will then use the slope and the y-intercept to graph the line.
Slope (m): Measures the steepness of a non-vertical line. It is sometimes refereed to as the rise/run or . It’s how fast and in what direction y changes compared to x.
y-intercept: The y-intercept is where a line passes through the y axis. It is always stated as an ordered pair (x,y). The x coordinate is always zero. The y coordinate can be taken from the “b” in y=mx+b.
Graphing The Linear Equation: y = 3x - 5
1) Find the slope: m = 3 ( m = 3 . = y .
1 x
2) Find the y-intercept: x = 0 , b = -5 ( (0, -5)
3) Plot the y-intercept
4) Use slope to find the next point: Start at (0,-5)
m = 3 . = y . ( up 3 on the y-axis
1 x ( right 1 on the x-axis
(1,-2) Repeat: (2,1) (3,4) (4,7)
5) To plot to the left side of the y-axis, go to y-int. and
do the opposite. (Down 3 on the y, left 1 on the x)
(-1,-8) Repeat: (-2,-11) (-3,-14)
6) Connect the dots.
Do Now on GP:
1) y = 2x + 1
2) y = -4x + 5
3) y = ½ x – 3
4) y = ⅔x + 2
Finding the equation of a line in slope intercept form (y=mx + b)
Example: Find the equation in slope intercept form of the line formed by (3,8) and (-2, -7).
A. Find the slope (m): B. Use m and one point to find b:
m = y2 – y1 y = mx + b
x2 – x1 m= 3 x= 3 y=8
m = -7 – 8 . -7 = 3(-2) + b
-2 – 3 -7 = -6 + b
+6 +6
m = -15 . -1 = b
-5
m= 3 y = 3x – 1
III. Special Slopes
A. Zero Slope B. No Slope (undefined slope)
* No change in Y * No change in X
* Equation will be Y = * Equation will be X =
* Horizontal Line * Vertical Line
Find equation in slope intercept form and graph:
1) (3,-2)(-6,-8) 6) m= 4 (-2,-5) 12) 16x -4y =36
2) (-6,10) (9,-10) 7) m= ⅔ (-6,-7) 13) 8x+24y = 96
3) (3,7) (3,-7) 8) m= -3/2 (8,-1) 14) y-7=2(x+1)
4) (7,-6)(-3,4) 9) m = 0 (4,3) 15) y+5=(2/5)(x-10)
5) (5,-9)(-5,-9) 10) m = undefined (-6, 5) 16) y-7= ¾ (x+12)
11) m=-3 (-4,19) 17) y-2=-3(x-2)
IV. Parallel and Perpendicular Lines:
A. Parallel Lines B. Perpendicular lines
* Do not intersect * Intersect to form right angles (90˚)
* Have same slopes * Slopes are negative reciprocals.
(Invert fraction and change sign)
(Products of slopes is –1)
Do in NB: For the given line, find a line that is parallel and passes through the given point. Then, find the equation of a line that is perpendicular and passes through the given point.
Given Line: Parallel: Perpendicular:
7) y = ⅓ x + 4 (6,1) ( -2,10)
8) y = 4x – 5 (2,13) (8.-5)
9) y = -⅔ x + 2 (-9,-11) (4,-1)
10) –5x + 6 (4,-27) (-10,6)
Practice Problems: a) Use the two points to find the equation of the line.
b) For the line found in part a, find a line that is parallel and passes through the given point.
c) Find the equation of a line that is perpendicular and passes through the given point.
Given Line: Parallel: Perpendicular:
1) (-5, 13) (3, -3) (4,-10) (2,7)
2) (-6,0) (3,6) (6,3) (6,-7)
3) (2,6)(-3,-19) (5,14) (5,5)
4) (-4,3) (-8,6) (-4, 10) (-6,-8)
5) (2,-5) (-2, -5) (8,-2) (4,-3)
6) (-9,-11)(6,9) (-3,-9) (-4,10)
7) (8,-3) (-4,9) (-2, 14) (6,-4)
8) (3,6)(3,-6) (11,-3) (5,2)
9) (4,-3)(-6,-8) (6,7) (-5,0)
10) (2,4)(-6,-12) (-3,-5) (-8,4)
11) Find the equation of the line parallel to y = 3x – 2, passing through (-2, 1).
12) Find the equation of the line perpendicular to y = -½x – 5, passing through (-2, -10)
13) Find the equation of the line parallel to y = -¼ x + 2, passing through (-8, 7)
14) Find the equation of the line perpendicular to y = (3/2)x + 6, passing through (-6, 1)
15) Find the equation of the line parallel to y = -5, passing through (2,7)
16) Find the equation of the line perpendicular to y = 5, passing through (6, -4).
17) Find the equation of the line parallel to x= 8, passing through (4, -9)
18) Find the equation of the line perpendicular to x = -3, passing through (6, -7).
Solve each system graphically:
19) y = -4x -5 23) y-2= (3/5)(x-10)
y = 2x -7 y+11 =2(x+7)
20) 6x + 3y =21 24) 6x + 9y = 45
12x + 16y = -48 9x +15y = 75
21) 12x – 6y = -6 25) x = 5
16x -8y = 40 y-12 = -3(x+2)
22) y= -4 26) 9x – 18y = 126
x = 7 y = -4
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