Calculus II, Section6.5, #18 Average Value ofa Function

Average Velocity The average rate of displacement. v ... do the calculus now and see that we get the same answer. Since the acceleration is constant, it can come through the integral sign. Integrating dt, just gives t evaluated at zero and the final time. v −v o=adt 0 t ∫⇒v−v o=adt 0 t ∫⇒v−v o=at 0 t⇒v−v o=a(t−0)⇒v−v o=at. So, in fact, we get the same result as we did ... ................
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