Wastewater Math Concepts - American Water College
Wastewater Math Concepts
Book 2 Intermediate Level Problems
Table of Contents
Page
Flow Problems
1
Grit Channel Problems
4
Sedimentation Basin, Tank, and Clarifier Problems
Detention Time
10
Surface Loading Rate
12
Weir Overflow Rate
15
Solids Loading
18
Trickling Filter Problems
Hydraulic Loading
21
Organic Loading
24
Removal Efficiency
27
Rotating Biological Contactors
Hydraulic Loading
30
Organic Loading
33
Activated Sludge Problems
Sludge Volume Index (SVI)
36
Pounds of Solids in Aeration Basin
39
Pounds of BOD Applied to Aeration Basin
42
Sludge Age
45
Pond Problems
Detention Time
48
Population Loading
51
Hydraulic Loading
54
Organic Loading
57
Chlorination Problems
Residual
60
Chlorinator Setting
62
Chemical Dose Problems
Polymer dose
64
Feed Pump Calibration and Setting
72
Blueprints
80
Final Exam
84
EQUIVALENTS AND FORMULAS
EQUIVALENTS
1 acre = 43,560 square feet
1 cubic foot of water = 7.48 gallons
1 gallon of water = 8.34
pounds
1 day = 1,440 minutes = 86,400 seconds
1 million gallons/day = 694 gallons/minute = 1.547 cubic feet/second = 3.069 acre-feet/day
1% = l0,000 mg/L
= 3.14
1 inch of mercury = 1.133 feet of water
1 pound/square inch = 2.31 feet of
water
I HP = 0.746 Kw = 550 ft-lb/sec = 33,000 ft-lb/min
FORMULAS
Area of rectangle = Length x Width
Area of circle = x Diameter2 = 0.785 x Diameter2
4 Volume of rectangular or circular tank with uniform depth = Area x Depth
Volume of cone = 1/3 x Base Area x Depth
Circumference = x Diameter
Velocity = Distance Time
Flow = Velocity x Area
Detention time = Volume Flow
Pounds/day = 8.34 x Flow, mgd x Concentration, mg/L
F/M = Pounds of BOD or COD applied per day Pounds of MLVSS under aeration
MCRT = Pounds of MLSS in secondary system (aeration tank + clarifier) Pounds of MLSS leaving secondary system per day (effluent + WAS)
Water HP = Flow, gpm x Total Head, ft 3960 gpm-ft HP
Brake HP = Power to electric motor x Motor efficiency
Volatile Solids Reduction, % = In ? Out x 100% In - (In x Out)
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