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Use Empirical Rule: 95% => Mean ± 2. standard deviation = (12-2*16.5, 12+2*16.5)=(-21%, 45%) Mark the mean, the answer you got from part (a) in the curve below and shade in the appropriate area that corresponds to the 95% referred to in part (a). Also sketch a Normal curve for part (a) in terms of Z. (Sketch Z = 0, the standardized score, and ... ................
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