F ( 2 , 5 8 ) = 2 9 . 6 0 P r o b > F = 0 . 0 0 0 0 R - s q u a r e d ...
_ c o n s . 4 4 4 9 3 5 1 2 . 1 0 5 5 4 6 0 . 2 1 0 . 8 3 3 M S E - 3 . 7 6 8 2 5 2 = 4 . 6 5 8 1 2 2. _ c o n s 1 . 9 8 0 4 7 9 2 . 3 1 4 8 2 8 0 . 8 6 0 . 3 9 6 - 2 ... ................
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