4.5 Graphing All Six Trig Functions
4.5 Graphing All Six Trig Functions
In this section we take a little time to completely describe the graphs of the six trig functions. We have
already focused on the sine and cosine functions, devoting an entire lecture to the sine wave. So in this
section we will look at the tangent function and then the reciprocals of sine, cosine and tangent, that is,
cosecant, secant and cotangent.
But first a note about notation. Up to this time we have viewed trig functions as functions of an
angle and have tended to reserve the letters x, y for coordinates on the unit circle. Now, however, it is
time to return to our original custom about variables in functions, using x as the input variable and y as
the output variable.
For example, when we write y = tan(x) we now think of x as an angle and y as a ratio of two sides
of
a
triangle.
In
this
case
x
is
the
old
and
y
is
the
old
y x
!
4.5.1 The tangent function
The tangent function
tan x
=
sin x cos x
has
a zero wherever sin x
=
0, that is,
whenever
x is . . . , -2, -, 0, , . . . , k, ...
where k is an integer. The tangent function is undefined whenever cos x = 0, that is, at the x-values
.
.
.
,
-
3 2
,
-
2
,
2
,
3 2
,
5 2
,
.
.
.
,
(2k+1) 2
,
...
(where
k
is
an
integer.)
Indeed, at these x-values, the tangent
function has vertical asymptotes.
Here is the graph of the tangent function.
Figure 20. The tangent function (blue curves) along with vertical asymptotes (dotted red lines)
When we discussed the sine wave, we also discussed concepts of period, amplitude and phase shift. The graph of y = sin x had period 2, amplitude 1 and phase shift 0. We observed earlier that the tangent function has period . This is clear from the unit circle definition of tangent and this period is visible in our graph.
It does not make sense to discuss the amplitude of the tangent function since the range of tangent is the full set of all real numbers, (-, ).
The domain of the tangent function is all real numbers except those where cos x = 0. We can write this in set notation as
3
3 3 5
. . . (- , - ) (- , ) ( , ) ( , ) . . . .
22
22 2 2
22
Since this domain is a union of an infinite number of open intervals (each interval of length ) then we
172
might write this union in a more compact form using a more general "iterated union" notation:
(2k - 1) (2k + 1)
Domain of the tangent function =
(
,
).
2
2
k=-
(We won't do much with these more general arbitrary unions in this class, but it is important to see this notation once or twice in a precalculus class.)
4.5.2 The graphs of secant and cosecant
The secant function is the reciprocal of cosine and so it has vertical asymptotes wherever cos x = 0. Since -1 cos x 1 then the reciprocal function, secant, is bounded away from the x-axis; whenever cos x is positive (but no larger than 1) then the secant is positive but greater than or equal to 1. Similarly whenever the cosine is negative (but not less than -1) the secant function is negative but less than or equal to -1.
Here is the graph of the secant function (in blue) with asymptotes as dotted red lines and the cosine function hiding in light yellow.
Figure 21. The secant function with asymptotes
The cosecant function is similar. The cosecant function is the reciprocal of the sine function. When
we investigated the sine and cosine functions, earlier, we observed that the cosine function is the sine
function
shifted
to
the
left
by
2
(that
is,
cos x
=
sin(x +
2
))
and
so
the
graph
of
the
sine
function
is
the
same
as
the
graph
of
the
cosine
function
shifted
to
the
right
by
2
.
If
the
graph
of
sine
is
achieved
by
shifting
cosine
to
the
right
by
2
then
the
graph
of
cosecant
is
the
same
as
that
of
the
secant
function
shifted
to
the
right
by
2
.
The graph of the cosecant function, with asymptotes, is drawn in the figure below.
173
Figure 22. The cosecant function with asymptotes
4.5.3 The cotangent function The cotangent is the reciprocal of tangent. Here is the graph of the cotangent function.
Figure 23. The cotangent function
We see from looking at the graph of cotangent that the graph of cotangent can be achieved by taking the
graph
of
the
tangent
function,
moving
it
left
(or
right)
by
2
and
then
reflecting
it
across
the
x-axis.Thus
cot(x) = - tan(x + ).
2
Another
way
to
see
this
is
to
recognize
that
since
cos x
=
sin(x
+
2
)
and
that
- sin x
=
sin(x
+
)
then
cot(x)
=
cos x sin x
=
sin(x + sin x
2
)
=
sin(x -
+
2
)
sin(x + )
=
sin(x + -
cos(x +
2
)
2
)
=
- tan(x +
).
2
174
4.5.4 Some worked problems
1. For each of the following functions, describe the transformation required to change the graph of the tangent function into the graph of the indicated function.
(a)
y
= tan(x -
2
)
(b)
y
= tan(2x -
2
)
(c)
y
= 5 tan(x -
2
)
+
1
(d)
y
= -2 tan(2x -
2
)
+
4
(e) y = cot(x)
(f )
y
= cot(x -
2
)
(g)
y
= cot(2x -
2
)
Solutions.
(a)
To
graph
y
= tan(x -
2
),
shift
the
graph
of
the
tangent
function
right
by
2
.
(b)
To
graph
y
= tan(2x -
2
),
shift
the
graph
of
the
tangent
function
right
by
4
and
then
shrink
the function by a factor of two in the horizontal direction. (Or first shrink the function by a
factor
of
2
in
the
horizontal
direction
and
then
shift
it
right
by
2
.
(c)
To
graph
y
=
5 tan(x -
2
)
+
1,
shift
the
graph
of
the
tangent
function
right
by
2
,
stretch
it
vertically by a factor of 5 and then move the function up 1.
(d)
To
graph
y
=
-2 tan(2x -
2
)
+
4,
shift
the
graph
of
the
tangent
function
right
by
4
,
then
shrink the function by a factor of two in the horizontal direction, stretch it by a factor of 2 in
the vertical direction and then shift it up by 4.
(e)
To
graph
y
= cot(x),
reflect
the
graph
of
y
= tan x
across
the
x-axis
and
shift
it
left
by
2
to
obtain the graph of the cotangent function.
(f )
To
graph
y
= cot(x -
2
),
first
reflect
the
graph
of
y
= tan x
across
the
x-axis
and
shift
it
left
by
2
to
obtain
the
graph
of
the
cotangent
function.
Finally,
shift
the
graph
right
by
2
.
(g)
To
graph
y
=
cot(2x
-
2
),
first
reflect
the graph
of
y
= tan x
across
the
x-axis and shift
it
left
by
2
to
obtain
the
graph
of
the
cotangent
function.
Then
shift
the
graph
right
by
4
and
then
shrink the function by a factor of two in the horizontal direction.
2. Find all solutions to the trig equation tan = 1
Solution. From looking at the unit circle, we see that = 45 = /4 is a solution to this equation. So also is = 225 = 5/4, the angle in the third quadrant with reference angle /4. But there are many more solutions; if we add 2 to , we get new angles that satisfy this equation. Therefore
5
{ 4
+
2k
:
k
Z}
{
4
+ 2k : k Z}
is the (infinite) set of all solutions.
However, recall that the tangent function has period . So we could simplify this answer by just
writing
{ 4
+
k
:
k
Z}
175
3. The angle has the property that sec = 2 and tan is negative. Identify the angle and then find all six trig functions of the angle .
Solution.
Since
the
secant
of
is
2
then
cos()
=
1 2
.
Since
the
tangent
of
is
negative
then
is
in
3
the fourth quadrant and we may assume = - . Then sin() = - and tan() = 3 and the
3
2
other functions are reciprocals of these.
4.5.5 Other resources on the graphs of the six trig functions
In the free textbook, Precalculus, by Stitz and Zeager (version 3, July 2011, available at stitz-) this material is covered in section 10.5.
In the free textbook, Precalculus, An Investigation of Functions, by Lippman and Rassmussen (Edition 1.3, available at ) this material is covered in section 6.2.
In the textbook by Ratti & McWaters, Precalculus, A Unit Circle Approach, 2nd ed., c. 2014 (here at ) this material appears in section ?? of chapter 5. In the textbook by Stewart, Precalculus, Mathematics for Calculus, 6th ed., c. 2012 (here at ) this material appears in sections 5.3 and 5.4.
There are a collection of videos on graphing the various trig functions here at Khan Academy.
Homework. As class homework, please complete Worksheet 4.5, Graphs of the Six Trig Functions available
through the class webpage.
176
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