Maximum and Minimum Values - Pennsylvania State University

1 = {(x,y)|x2 + y2 2} is closed because it includes its boundary while D 2 = {(x,y)|x2 + y2 < 2} is not closed because it does not. D 1 D 2 To find the absolute maximum and absolute minimum, follow these steps: 1. Find the the critical points of f on D. 2. Find the extreme values of f on the boundary of D. 3. ................
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