De nition of the De nite Integral - University of Illinois ...
Definition of the Definite Integral
If f is defined on [a, b], we divide [a, b] into n subintervals of equal width x = (b - a)/n. We let x0, x1, x2, . . . , xn be the endpoints of these subintervals and we let x1, x2, x3, . . . , xn be any sample points in these subintervals. Then the definite integral of f from a to b is
b
n
a
f (x) dx = lim
n
f (xk)x
k=1
provided that this limit exists and gives the same value for all possible choices of sample points. If it
does exist, we say that f is integrable on [a, b].
Theorem: If f is continuous on [a, b], or if f has only a finite number of jump discontinuities, then f is
b
integrable on [a, b]; that is, the definite integral f (x) dx exists.
a
Theorem: If f is integrable on [a, b], then
b
n
a
f (x) dx = lim
n
f (xk)x
k=1
b-a where x = n and xk = a + kx
Properties of the Definite Integral (assume f and g are continuous)
a
b
? f (x) dx = - f (x) dx
b
a
a
? f (x) dx = 0
a
b
? c dx = c(b - a)
a
b
b
? cf (x) dx = c f (x) dx
a
a
b
b
b
? [f (x) + g(x)] dx = f (x) dx + g(x) dx
a
a
a
b
b
b
? [f (x) - g(x)] dx = f (x) dx - g(x) dx
a
a
a
b
c
b
? f (x) dx = f (x) dx + f (x) dx
a
a
c
b
? If f (x) 0 for a x b, then f (x) dx 0
a
b
b
? If f (x) g(x) for a x b, then f (x) dx g(x) dx
a
a
b
? If m f (x) M for a x b, then m(b - a) f (x) dx M (b - a)
a
Fundamental Theorem of Calculus: Suppose f is continuous on [a, b].
x
? Part 1: If g(x) = f (t) dt, then g (x) = f (x).
a
b
? Part 2: f (x) dx = F (b) - F (a) where F is any antiderivative of f (that is, F = f ).
a
b
Part 2 is sometimes written as F (x) dx = F (b) - F (a) and called the Net Change Theorem since
a
the definite integral of a rate of change is equal to the net change.
List of Indefinite Integrals
? k dx = kx + C
? xn dx = xn+1 + C n+1
?
x-1 dx =
1 dx = ln |x| + C
x
? ex dx = ex + C
? ax dx = ax + C ln (a)
(where k is any constant) (where n is any constant except -1)
(where a is any positive constant except 1)
? sin (x) dx = - cos (x) + C
? cos (x) dx = sin (x) + C ? sec2 (x) dx = tan (x) + C ? csc2 (x) dx = - cot (x) + C
? sec (x) tan (x) dx = sec (x) + C
? csc (x) cot (x) dx = - csc (x) + C
1 ? 1 + x2 dx = arctan (x) + C
1
?
dx = arcsin (x) + C
1 - x2
1
?
dx = arcsec (x) + C
x x2 - 1
? sinh (x) dx = cosh (x) + C
(hyperbolic function to be discussed after third test)
? cosh (x) dx = sinh (x) + C
(hyperbolic function to be discussed after third test)
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